Answer 54 is the correct answer
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The answer: " k = -10 " .
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Given: (- 6/5) k = 12 ; Solve for: "k" ;
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Multiply each side of the equation by "5" ; to get rid of the "fraction":
5* (-6/5) k = 12 * 5 ;
to get:
- 6 k = 60 ;
Divide each side of the equation by "-6" ;
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- 6 k / 6 = 60 / 6 ;
to get:
-1 k = 10 ;
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Divide each side of the equation by "-1" ;
to isolate "k" on one side of the equation ; and to solve for "k" ;
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- 1 k / -1 = 10 / -1 ;
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to get: k = -10 .
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Answer:
Step-by-step explanation:
The domain of that function is all real numbers. The x values will drop into negative infinity and will grow to positive infinity.
The range is found from the vertex form of a parabola, which is
![y=(x-h)^2+k](https://tex.z-dn.net/?f=y%3D%28x-h%29%5E2%2Bk)
where h indicates side to side movement of the vertex and k indicates up or down. Our function has a +3 at the end of it and is positive (so it opens upwards), so the range is y ≥ 3.
To find the inverse of that function, switch the x and y coordinates and solve for the new y. Let f(x) be y, then switch the x and y:
![x=y^2+3](https://tex.z-dn.net/?f=x%3Dy%5E2%2B3)
Now solve for the new y:
y = ±![\sqrt{x-3}](https://tex.z-dn.net/?f=%5Csqrt%7Bx-3%7D)
To find the domain of a radical, set the radicand greater than or equal to 0 and solve for x (this is because the radicand cannot be a negative number or we are dealing with imaginary numbers and that's not what you want. BTW, a radicand is the term under the radical sign).
x - 3 ≥ 0 so x ≥ 3. The domain of the inverse is all real numbers greater than or equal to 3.
This is a sideways parabola (the inverse is), and it opens to the right starting at the x value of 3. It will grow into positive values of y to infinity and will drop into negative values of y into negative infinity.
Just a little trick here to remember, and it ALWAYS holds true: the domain of a function is the range of its inverse, and the range of a function is the domain of its inverse. Look to our solution for your problem here and you'll see that it is true.
-68x + p = qx + 34
p - 34 = qx + 68x <em>added 68x to both sides & subtracted 34 from both sides.</em>
p - 34 = x(q + 68)
![\frac{p - 34}{q + 68} = x](https://tex.z-dn.net/?f=%5Cfrac%7Bp%20-%2034%7D%7Bq%20%2B%2068%7D%20%3D%20x)
The denominator cannot be equal to zero so q + 68 ≠ 0 ⇒ q ≠ -68
You didn't upload the options but look for the one that has q = -68.