Which of these will melt the fastest
1 answer:
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<h3>Answer:</h3>
The mole fraction of carbon dioxide is 0.0559
<h3>Explanation:</h3>- Mole fraction of a gas in a mixture of gases its given by dividing the number of moles of the gas by the total number of moles of the mixture.
In this case, we are given a mixture of N₂, CO₂ and He
To find the mole fraction of CO₂, first we need to calculate the total number of moles in the mixture.
Individual number of moles for each gas are;
Moles = mass ÷ Molar mass
Therefore;
Nitrogen gas (N₂)
Mass =18.0 g
Molar mass = 28.02 g/mol
= 0.642 moles N₂
Helium gas (He)
Mass = 50.5 g
Molar mass = 4.0 g/mol
= 12.625 moles He
Carbon dioxide (CO₂)
Mass = 34.6 g
Molar mass = 44.01 g/mol
= 0.786 moles CO₂
Therefore;
The total number of moles in the mixture;
= 0.642 moles + 12.625 moles + 0.786 moles
= 14.053 moles
Thus;
The mole fraction of CO₂= Moles of CO₂ ÷ Total number of moles
= 0.786 moles ÷ 14.053 moles
= 0.0559
Hence the mole fraction of carbon dioxide is 0.0559
Solution :
Given :
Initial temperature of the refrigerant is :
= ( 39.37 + 273 ) K
= 312.3 K
Room which is maintained at constant temperature is :
= (22+273) K
= 295 K
The thermal energy transferred to the room is :
Q = 400 kJ
=
Therefore, the total entropy generation during the thermal energy process is :
Here, -Q = heat is leaving the system maintained at a temperature of K.
+Q = heat is entering the system maintained at a temperature of K.
Therefore, substituting the values :
= [-1280.8197 + 1355.9322]
= 75.1125 J/K
= 0.0751125 kJ/K
= 0.075 kJ/K
Answer:
z = 18,46%
Explanation:
First we need to discover the mole number of the O2 produced so we use PV=nRT
734 torr * 57.2*10^-3 L = n 62.3637 * 295.15 K
n =
n =
n = 2,28 * 10^-3 mole
The reaction to the decomposition is:
2 NaClO3 --> 2 NaCl + 3 O2
2 mole NaClO3 - 3 moles O2
x - 2,28*10^-3 moles O2
X= 1,52*10^-3 moles of NaClO3
1 moles of NaClO3 - 106,44 g
1,52*10^-3 moles of NaClO3 - y
y = 0,1617 g
0,8765 g - 100%
0,1617 g - z
z = 18,46%