Answer:
B a lever because it can move up and down
Explanation:
Answer:
Kindly check explanation
Explanation:
(a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.
(a) μMN = (10^-6 * 10^6) = 10^(-6 + 6) = 10^0 = N
b) N/μm = N / 10^-6 m = 10^6 * N/m = MN/m
(c) MN/ks2 = 10^6N / (10^3 s)^2
10^6 N / 10^6s^2 = 10^6 * 10^-6 N /s^2 = N/s^2
D) kN/ms = 10^3N / 10^-3 s = 10^3 * 10^3 * N/s = 10^6N / s = MN/s
2)
a) 0.000431kg = 431 × 10^6 kg = 431 * 10^9g = 431Gg
b) 35.3 × 10^3 N
10^3 = kilo(K)
35.3 KN
C) 0.00532km = 5.32 * 10^3 km = 5.32 * 10^3 * 10^3 = 5.32 * 10^6 = 5.32Mm
3) Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).
a) Mg/ms = 10^6g / 10^-3s = 10^6 * 10^3 g/s = 10^9 g/s = Gg/s
b) N/nm = N / 10^-9 m = 10^9 N/m = GN/m
c) mN/(kg⋅μs) = 10^6N / kg(10^-6s) = 10^12N/(kg.s)
= TN/(kg.s)
It’s true because convenience stores are more expensive so that means overall the items would be more expensive.
Answer:
Both the technicians are correct.
Explanation:
As the pressure increases the temperature will also increase in accordance with the Boyle's law hence greater amount of heat is formed.
When the temperature increases the intermolecular spaces increase as the molecules of the fuel gain energy and their kinetic energy increases. This is limited to temperatures below dissociation/combustion temperature of diesel .
Answer:
At the point when the quantity of bit strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just part strings to processors and not client level strings to processors. At the point when the quantity of part strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used all the while. Be that as it may, when a part string obstructs inside the portion (because of a page flaw or while summoning framework calls), the comparing processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, in this way expanding the use of the multiprocessor system.When the quantity of part strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just bit strings to processors and not client level strings to processors. At the point when the quantity of bit strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used at the same time. Be that as it may, when a part string hinders inside the piece (because of a page flaw or while summoning framework calls), the relating processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, along these lines expanding the usage of the multiprocessor framework.
