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topjm [15]
3 years ago
6

Two nuclei join to form a larger nucleus during which process

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

The answer is nuclear fusion.

Explanation:

pentagon [3]3 years ago
4 0

nuclear fusion- produces huge amounts of energy.

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What major region does this profile<br> most likely represent?
alexdok [17]

Answer:

A mid ocean ridge possibly a plate margin spreading area

Explanation:

6 0
2 years ago
Will upvote
Debora [2.8K]
Bike
because it involves lots of angular mechanics that allow it to balance itself when moving.

all other examples have a constant force being applied into the system which is very easy to formulate, therefore they are simple machines.
3 0
3 years ago
8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.
mamaluj [8]

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle (p), measured in centimeters, is represented by the following formula:

p = 2\cdot (w+l) (1)

Where:

w - Width, measured in centimeters.

l - Length, measured in centimeters.

If we know that w = 6.4\,cm and l = 8.3\,cm, then the perimeter of the rectangle is:

p = 2\cdot (6.4\,cm+8.3\,cm)

p = 29.4\,cm

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter (\Delta p), measured in centimeters, is estimated by differences. That is:

\Delta p = 2\cdot (\Delta w + \Delta l)  (2)

Where:

\Delta w - Uncertainty in width, measured in centimeters.

\Delta l - Uncertainty in length, measured in centimeters.

If we know that \Delta w = 0.2\,cm and \Delta l = 0.2\,cm, then the uncertainty in perimeter is:

\Delta p = 2\cdot (0.2\,cm+0.2\,cm)

\Delta p = 0.8\,cm

The uncertainty in its perimeter is 0.8 centimeters.

5 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec
juin [17]

Answer:

Explanation:

Given that:

angular frequency = 11.3 rad/s

Spring constant (k) = = \omega^2  \times m

k = (11.3)² m

k = 127.7 m

where;

x_1 = 0.065 m

x_2  = 0.048 m

According to the conservation of energies;

E_1=E_2

∴

\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2

kx_1^2 = mv_2^2 + kx_2^2

(127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2

0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325  - 0.2942208 = v_2^2 \\ \\  v_2^2 = 0.2453117 \\ \\  v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}

4 0
3 years ago
A friend on skis stands still on level ground, with dry 0.00°C with a coefficient of static friction of 0.0300. How hard would y
Salsk061 [2.6K]

Answer:

20.6 N

Explanation:

Friction equals normal force times coefficient of friction.

F = Fn μ

On level ground, normal force equal weight.

Fn = W

Therefore:

F = W μ

F = (685 N) (0.0300)

F = 20.6 N

6 0
3 years ago
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