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topjm [15]
3 years ago
6

Two nuclei join to form a larger nucleus during which process

Physics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

The answer is nuclear fusion.

Explanation:

pentagon [3]3 years ago
4 0

nuclear fusion- produces huge amounts of energy.

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The initial velocity of a truck is 10 m/s. How long must it accelerate at a constant acceleration of 2m/s2 before its average ve
Yuliya22 [10]

Answer:

10s

Explanation:

vf = vi+at

30=10+2t

20= 2t

t = 10 s

7 0
2 years ago
Anybody know the answer to this ?
Firlakuza [10]

Answer:

4 ampere

Explanation:

I= v/R

=12/3

= 4 amp

5 0
3 years ago
The product of voltage times amperage is known as what?
Usimov [2.4K]

Answer:

Power=V*I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation

Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I

5 0
2 years ago
An object moving with a speed of 35 m/a and has a kinetic energy of 1500j, what is the mass of the object
EleoNora [17]

Explanation:

Speed or velocity (V) = 35 m/s

Kinetic energy (K. E) = 1500 Joule

mass (m) = ?

We know

K.E = 1/2 * m * v²

1500 = 1/2 * m * 35²

1500 * 2 = 1225m

m = 3000 / 1225

m = 2.45 kg

The mass of the object is 2.45 kg

Hope it will help :)

5 0
3 years ago
two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel .calculate the equivalent series resist
Novosadov [1.4K]

Explanation:

Given that,

Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.

For series combination,

R_{eq}=R_1+R_2

For parallel combination,

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

When 6 ohm and 3 ohm are in series,

R_s=6+3\\\\R_s=9\ \Omega

When 6 ohm and 3 ohm are in paralle,

\dfrac{1}{R_p}=\dfrac{1}{6}+\dfrac{1}{3}\\\\R_p=2\ \Omega

So, the equivalent resistance in series combination is 9 ohms and in parallel combination it is 2 ohms.

6 0
2 years ago
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