Answer:
Time taken for car to stop = 0.89 seconds (Approx.)
Explanation:
Given:
Mass of car = 1100 kg
Speed of car = 15 m/s
Impact force = 185,000 N
Find:
Time taken for car to stop
Computation:
Change in momentum of car = M(v) - M(u)
Change in momentum of car = 1100(0) - 1100(15)
Change in momentum of car = -16,500
Time taken for car to stop = I Change in momentum of car I / Impact force
Time taken for car to stop = I-16,500I / 185,000
Time taken for car to stop = 0.89 seconds (Approx.)
<h3>
Answer:</h3>
800 meters
<h3>
Explanation;</h3>
<u>We are given;</u>
- Speed as 40 m/s
- Time as 20 seconds
We are required to determine the distance traveled
- Speed refers to the rate of change in distance.
- It is given by;
Speed = Distance ÷ time
Rearranging the formula;
Distance = speed × time
In this case;
Distance = 40 m/s × 20 sec
= 800 meters
Thus, the distance traveled by the car is 800 m
I’d say a negative charge cause opposites attract but I’m not sure
Answer:
A) Φ = 0
, B) T = 7.76 s
Explanation:
A) to find the value of the phase constant replace the value
0 = a sin (b (0- 0) + Φ)
0 = sin Φ
Φ = sin⁻¹ 0
Φ = 0
B) the period is defined by time or when the movement begins to repeat itself
So that the sine function is repeated when the angle passes 2pi
b (x- ct) = 2pi
If we are at a fixed point x = 0
b c t = 2pi
t = 2π / bc
Let's calculate
T = 2π / (33.05 245)
T = 7.76 s
