Answer:
Part A
The green plant is a producer
The grasshopper is a herbivore
The Rat is a Omnivore
The snake is a Carnivore
The eagle is a Carnivore
The mushroom is a Decomposer
Part B
The arrow between each organism indicates the direction of energy flow which shows the direction in which the energy transfer takes place from one organism to the next, with the general source of energy for all animals being the Sun.
Part C
A sample food chain can be presented as follows;
Sun, Green plants → worms → Frogs → Snakes → Coyotes → Bears → Tigers → Mushroom → Plants
Explanation:
The crimes where the person
Answer:
co is colbalt
Explanation:
Cobalt
Cobalt is a chemical element with symbol Co and atomic number 27.
In the modern periodic table, the elements are arranged according to their atomic number - not their relative atomic mass.
In the periodic table the elements are arranged into:
rows, called periods, in order of increasing atomic number
vertical columns, called groups, where the elements have similar properties
Answer:
![\large \boxed{\text{5.8 L}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B5.8%20L%7D%7D)
Explanation:
Data:
p₁ = 1 bar; V₁ = 5 L; T₁ = 0 °C
p₂ = 1 bar; V₂ = ?; T₂ = 45 °C
The pressure and the number of moles are constant, so, to calculate the volume, we can use Charles' Law.
![\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BV_%7B1%7D%7D%7BT_%7B1%7D%7D%20%3D%20%5Cdfrac%7BV_%7B2%7D%7D%7BT_%7B2%7D%7D)
Calculations:
(a) Convert temperatures to kelvins
T₁ = (0 + 273.15) K = 273.15 K
T₂ = (45 + 273.15) K = 318.15 K
(b) Calculate the new volume
![\begin{array}{rcl}\dfrac{V_{1}}{T_{1}} &= &\dfrac{V_{2}}{T_{2}}\\\\\dfrac{5}{273.15} &= &\dfrac{V_{2}}{318.15}\\\\0.018 &= &\dfrac{V_{2}}{318.15}\\\\{ V_{2}} &=& 0.018 \times 318.15\\&=& \textbf{5.8 L}\\\end{array}\\\text{The volume will be $\large \boxed{\textbf{5.8 L}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Cdfrac%7BV_%7B1%7D%7D%7BT_%7B1%7D%7D%20%26%3D%20%26%5Cdfrac%7BV_%7B2%7D%7D%7BT_%7B2%7D%7D%5C%5C%5C%5C%5Cdfrac%7B5%7D%7B273.15%7D%20%26%3D%20%26%5Cdfrac%7BV_%7B2%7D%7D%7B318.15%7D%5C%5C%5C%5C0.018%20%26%3D%20%26%5Cdfrac%7BV_%7B2%7D%7D%7B318.15%7D%5C%5C%5C%5C%7B%20V_%7B2%7D%7D%20%26%3D%26%200.018%20%5Ctimes%20318.15%5C%5C%26%3D%26%20%5Ctextbf%7B5.8%20L%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20volume%20will%20be%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B5.8%20L%7D%7D%24%7D)