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kotykmax [81]
4 years ago
13

DISCUSSION QUESTION

Chemistry
1 answer:
andrey2020 [161]4 years ago
6 0
No, I don’t think so. My reason being that some of these viruses are not harmful, an example is bacteriophage which kills bacteria.
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Please answer fast and correct. (15 points)
denis23 [38]

Answer:

the frequency with get lower

6 0
4 years ago
Read 2 more answers
Water is 11% hydrogen and 89% oxygen by mass. How many grams of oxygen are in a 250 g glass of water?
SCORPION-xisa [38]
222.5 g

I did it like this:

X/250= 89/100=
22250/100=
222.5
4 0
3 years ago
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Which of the following forms a new substance? melting, evaporating, freezing or burning
Slav-nsk [51]
It would be burning be cause when you freeze, evaporate, or melt anything it is just changing how fast the atoms are moving . Think of it like water, ice, and steam, they are all the same thing but in different forms because of melting, evaporating,and melting. Burning is breaking it down.
4 0
4 years ago
Read 2 more answers
Identify the combustion reaction
Paladinen [302]

Answer:

The combustion reaction is the last one, with the C4H12 compound.

Remember that all the combustion reactions has the oxygen as a substract and for products, you'll have CO2 and water.

Explanation:

3 0
3 years ago
(15 points). The oxidation of glucose provides the principal energy source for animal cells. The reactants are glucose [C6H12O6(
miss Akunina [59]

Answer:

Check the explanation

Explanation:

The balanced reaction

C6H12O6(s) + 6O2(g) = 6CO2(g) + 6H2O(l)

Standard heat of reaction

Hrxn = 6*Hf(CO2) + 6*Hf(H2O) - 6*Hf(O2) - Hf(C6H12O6)

= 6*(-393.5) + 6*(-285.8) - 6*(0) - (-1274.4)

= - 2801.4 kJ/mol

Part b

Energy consumed by a person = 150 kJ/kg x 57 kg = 8550 kJ

Moles of glucose required = 8550 kJ / (2801.4 kJ/mol)

= 3.052 mol

Mass of glucose required = moles x molecular weight

= 3.052 mol x 180.156 g/mol

= 549.84 g

Part c

1 person requires = 3.052 mol

275 million person require = 275*10^6*3.052 = 8.39 x 10^8 mol

From the stoichiometry of the reaction

1 mol glucose produces = 6 mol CO2

8.39 x 10^8 mol glucose produces = 6*8.39*10^8

= 5.036 x 10^9 mol CO2

Mass of CO2 produced = moles x molecular weight

= 5.036 x 10^9 mol x 44 g/mol

= 2.22 x 10^11 g x 1kg/1000g

= 2.22 x 10^8 kg x 1million/10^6

= 222 million kg

5 0
4 years ago
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