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3 years ago

1. Which population of organisms depends on eating another population of organisms for

Chemistry

1 answer:

Aloiza [94]3 years ago

8 0

Answer:

predation

Explanation:

Predation An interaction in which one organism kills another for food. Prey An organism that is killed and eaten by another organism.

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I need help fast...........

guapka [62]

Answer:

I think its might be 1 because the ionic numbers for CA is +2 and for P its +3

8 0

3 years ago

Convert mass to moles for both reactants. (round to 2 significant figures.)

Maslowich

Answer:

Explanation:

Given parameters:

Mass of CuCl₂ = 2.50g

Mass of Al = 0.50g

Unknown:

Number of moles of CuCl₂ and Al = ?

Solution:

To solve this problem, we must understand that the number of moles is a fundamental property used in stoichiometry calculations.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of CuCl₂ = 63.6 + 2(35.5) = 134.5g/mole

Molar mass of Al = 26.98g/mole

Number of moles of CuCl₂ = $\frac{2.5}{134.5}$ = 0.019moles

Number of moles of Al = $\frac{0.5}{26.98}$ = 0.019moles

4 0

3 years ago

Read 2 more answers

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

300 moles of sodium nitrite are needed for a reaction. the solution is 0.450 m. how many ml are needed?

miv72 [106K]

Answer:

$\boxed{\text{667 000 mL}}$

Explanation:

$\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\c = \dfrac{n}{v}$

Data:

c = 0.450 mol·L⁻¹

n = 300 mol

Calculation:

$\begin{array}{rcl}0.450 & = & \dfrac{300}{V}\\\\0.450V& = & 300\\\\V & = & \dfrac{300}{0.450}\\\\V & = & \text{667 L} =\textbf{667 000 mL}\end{array}\\\text{The volume of solution needed is }\boxed{\textbf{667 000 mL}}$

4 0

3 years ago

What would be the formula for diphosphorus pentoxide? A. PO5 B. P2O5 C. P5O D. P5O2

Dovator [93]

I am sure, the answer is variant B.

6 0

3 years ago

Read 2 more answers