Answer:
a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀.
Explanation:
<em>Which statement below is true?
</em>
<em>a) At a given temperature, C₂H₆ has a higher vapor pressure than C₄H₁₀. </em>TRUE. C₂H₆ has a lower molar mass than C₄H₁₀ and a higher vapor pressure at most temperatures.
<em>b) The strongest intermolecular attractive forces present in liquid CCl₄ are dipole-dipole forces.</em> FALSE. CCl₄ is nonpolar, so the strongest intermolecular forces are dispersion forces.
<em>c) HCl has a higher boiling point than LiCl.</em> FALSE. LiCl (ionic compound) has a higher boiling point than HCl (covalent compound).
<em>d) H₂O has a greater polarizability than H₂Se.</em> FALSE. Se has a larger atomic radius than O which is why H₂Se has a greater polarizability than H₂O.
<em>e) In general, the stronger the intermolecular attractive forces, the lower the ∆Hºvap.</em> FALSE. In general, the stronger the intermolecular attractive forces, the higher the ∆Hºvap.
Answer:
14. This body system allows for movement by contracting.
A. Respiratory
B. Muscular
C. Skeletal
D. Endocrine
→B.Mascular
15. This body system protects organs and provides shape and support
A. Respiratory
C. Skeletal
B. Muscular
D. Endocrine
→C.Skeleton
16. The Magnification Power of High-Power Objectives.
A. 4 X
C. 10 X
D. 50 X
B. 40 X
→B.40x
17. The Magnification Power of Low Power Objectives.
A 4X
C. 10 X
B. 43 X
D. 50 X
→C.10x
Answer:
Given the reaction NH3 + O2 = NO + H2O, 3.25 g of NH3 is allowed to react with 3.50 g of O2. Which reactant is the limiting reagent? How many grams of H2O are formed? How much of the excess reactant remains after the reaction?
Answer:
160 mL
Explanation:
Given data:
Molarity of NaOH = 0.105 M
Volume of H₂SO₄ = 40.0 mL (40.0/1000 = 0.04 L)
Molarity of H₂SO₄ = 0.210 M
Volume of NaOH required = ?
Solution:
Number of moles of of H₂SO₄:
Molarity = number of moles / volume in L
0.210 M = number of moles / 0.04 L
Number of moles = 0.210 mol/L × 0.04 L
Number of moles = 0.0084 mol
now we will compare the moles of H₂SO₄ with NaOH.
H₂SO₄ : NaOH
1 : 2
0.0084 : 2/1×0.0084 = 0.0168 mol
Volume of NaoH:
Molarity = number of moles / volume in L
0.105 M = 0.0168 mol / Volume in L
Volume in L = 0.0168 mol / 0.105 M
Volume in L = 0.16 L
Volume in mL:
0.16 L × 1000 mL/ 1L
160 mL