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anyanavicka [17]
3 years ago
7

3. A force is exerted on a positively-charged particle that moves the particle in the direction opposite to that of an electric

field. Which one of the following statements concerning the work performed in this movement is true? a) The work done on the particle has a positive sign. b) No work is done on such a charged particle, if it is moved in a direction that is parallel or anti-parallel to an electric field. c) The work done on the particle has a negative sign. d) One cannot answer this question without knowing the kind of particle involved
Physics
1 answer:
NikAS [45]3 years ago
8 0

Answer:

a) The work done on the particle has a positive  sign.

Explanation:

When a positive charge is placed in a electric field , a force is exerted by electric field along the direction of the electric field . But the external force is acting on it so that displacement is opposite to the field . That means the external force is acting opposite to electric force on the charged particle.

The displacement is along the external force applied so both force and displacement are positive . Hence work done is positive .

Work done by electric field is negative , because displacement and electric force are opposite.

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Ahmed fills a basket with shopping weighing 10 kg. How much work is being done on the shopping basket when he lifts it verticall
NISA [10]

The work done by the shopping basket is 147 J.

<h3>When is work said to be done?</h3>

Work is said to be done whenever a force moves an object through a certain distance.

The amount of work done on the shopping basket can be calculated using the formula below.

Formula:

  • W = mgh

Where:

  • W = Amount of work done by the basket
  • m = mass of the shopping basket
  • h = height of the shopping basket
  • g = acceleration due to gravity.

Form the question,

Given:

  • m = 10 kg
  • h = 1.5 m
  • g = 9.8 m/s²

Substitute these values into equation 2

  • W = 10(1.5)(9.8)
  • W = 147 J.

Hence, The work done by the shopping basket is 147 J.

Learn more about work done here: brainly.com/question/18762601

6 0
2 years ago
Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
State any two effects of gravitational force​
Dmitry_Shevchenko [17]
Connection to Big Idea about energy: Gravity creates gravitational potential energy. Gravitational energy relies on the masses of two bodies and their distance.

Connection to Big Idea about the universe: Gravitational force is exerted by all objects with mass throughout the Universe. It is what keeps the Earth and the planets in orbit around the Sun, and our Solar System in orbit around the centre of the Milky Way. Gravity is one of the forces involved in the birth of stars, their evolution and finally their death.

Connection to Big Idea about Earth: The gravitational force is responsible for many physical properties of Earth and consequently it affects the existence and the properties of living creatures on it. For instance, the existence, the chemical composition and the structure of Earth’s atmosphere was determined by Earth’s gravitational force.

3 0
3 years ago
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
In an experiment, a torque of a known magnitude is exerted along the edge of a rotating disk. The disk rotates about its center.
lisabon 2012 [21]

Answer:

B) The amount of time the torque is applied to the disk, because the time interval is related to the angular impulse of the disk.

Explanation:

Angular impulse = Torque x time

= change in angular momentum

So,

Torque x time  = change in angular momentum

change in angular momentum = Torque x time

Torque is already known .

Hence to know the change in angular momentum what is needed to know is time duration of torque acting on the body .

3 0
3 years ago
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