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8090 [49]
3 years ago
6

What is the oxidation state of s in s2o3 2-

Chemistry
1 answer:
Yanka [14]3 years ago
6 0
Let x be the oxidation state of S.

Therefore,
2x + 3(-2) = -2 
2x = -2 + 6 
2x = 4
x =2.

Hence oxidation state of S is +2.

Hope this helps!
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zhenek [66]
Answer: option C. the number of electrons in the atom.

Given that the charge of a proton is the same that the charge of an electron, to be neutral the number of protons has to be the same than the number of electrons.


4 0
3 years ago
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Write the chemical formula for disilicon hexabromide.
Rasek [7]

Answer:

Br6Si2

Explanation:

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3 years ago
Apples reproduce naturally by sexual reproduction.How does this explain why there are many types of apples be sure to use use me
kvasek [131]

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could be a that the apple produced a seed with genetic mutation in chromosome during the process meiosis.

Explanation:

6 0
3 years ago
How many liters of water can be made from 55 grams of oxygen gas and an excess of hydrogen at a pressure of 12.4 atm and a tempe
polet [3.4K]
First, we need the no.of moles of O2 = mass/molar mass of O2
                                                             = 55 g / 32 g/mol
                                                             = 1.72 mol
from the balanced equation of the reaction:
2H2 (g) + O2(g) → 2H2O(g)
we can see that the molar ratio between O2: H2O = 1: 2 
So we can get the no.of moles of H2O = 2 * moles of O2
                                                                  = 2 * 1.72 mol
                                                                  = 3.44 mol
So by substitution by this value in ideal gas formula:
PV = nRT

when P = 12.4 atm  & n H2O = 3.44 mol & R= 0.0821 & T = 85 + 273=358K

12.4 atm *V = 3.44 * 0.0821 * 358 = 8.15 L
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4 0
4 years ago
How many photons are produced in a laser pulse of 0.862 J at 691 nm?
Inga [223]
To calculate how many photons are in a certain amount of energy (joules) we need to know how much energy is in one photon.
Start by using two equations:
Energy of a photon = Frequency * Planck's constant (6.626 * 10^(-34) J-s)
Speed of light (constant 3 * 10^8 m/s) = Frequency * Wavelength
Which means:
frequency = Speed of Light / Wavelength
So energy of a photon = (Speed of light * Planck's constant)/(Wavelength)
You may have seen this equation as E = hc/<span>λ</span>
We have a wavelength of 691 nm or 691 * 10^-9 meters
So we can plug in all of our knowns:
E = (6.626 * 10^(-34) J-s) * (3.00 * 10^8 m/s) / (691 * 10^-9 m) = 
2.88 * 10^(-19) joules per photon
Now we have joules per photon, and the total number of joules (0.862 joules)
,so divide joules by joules per photon, and we have the number of photons:
0.862 J/ (2.88 * 10^(-19) J/photon) = 3.00 * 10^18 photons.

4 0
3 years ago
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