Question

An organic compound of relative molecular mass 46,on analysis was found to contain 52.0% carbon, 13.3% hydrogen and 34.7% oxygen

Answer 1

Answer:

Empirical formula is C₂H₆O.

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Given data:

Percentage of hydrogen = 13.3%

Percentage of carbon = 52.0%

Percentage of oxygen = 34.7%

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 13.3 / 1.01 = 13 .17

Number of gram atoms of O = 34.7 / 16 = 2.17

Number of gram atoms of C = 52.0 / 12 = 4.3

Atomic ratio:

            C                     :          H             :           O

           4.3/2.17            :     13.17/2.17     :       2.17/2.17

            2                      :        6               :        1

C : H : O = 2 : 6 : 1

Empirical formula is C₂H₆O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 46 / 158

The relative molecular mass of compound is not correct.