Suppose you increase the height of the object without changing its depth under water. What will happen to the force due to press
1 answer:
Answer:Remains same
Explanation:
Given
It is given that the depth is constant and we are only increasing the height of object submerged in the water
thus Force due to Pressure remains same as this force depends upon the depth of object with respect to free surface of Fluid.
Pressure at a depth h with density of fluid is given by
and
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Answer:
Explanation:
The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.
where:
w = weight [N]
m = mass = 0.06 [kg]
g = gravity acceleration = 10 [N/kg]
Therefore:
By Hooke's law we know that the force in a spring can be calculated by means of the following expression.
where:
k = spring constant [N/m]
x = deformed distance = 6 [cm] = 0.06 [m]
We can find the spring constant.
Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.
Since this force is equal to the weight, we can now determine the gravitational acceleration.