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kipiarov [429]
3 years ago
7

Solve the equation 1/3m+6m-9/3m=3m-3/4m

Mathematics
1 answer:
vekshin13 years ago
3 0
M
=
0

O
r

m
=
23
15

Explanation:
1
3
m
+
6
m
−
9
3
m
=
3
m
−
3
4
m



⇒
1
+
6
m
−
9
3
m
=
3
m
−
3
4
m





⇒
−
8
+
6
m
3
m
=
3
m
−
3
4
m





⇒
(
−
8
+
6
m
)
×
4
m
=
(
3
m
−
3
)
×
3
m





⇒
−
32
m
+
24
m
2
=
9
m
2
−
9
m





⇒
−
32
m
+
24
m
2
−
9
m
2
+
9
m
=
0





⇒
15
m
2
−
23
m
=
0





⇒
m
(
15
m
−
23
)
=
0



m
=
0



Or


15
m
−
23
=
0
⇒
15
m
=
23
⇒
m
=
23
15
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Answer: B.  |x-100| = 25

Explanation:

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The value of x represents where the train is. So if we had say x = 85, then it would be at location 85 on the number line. Writing |x-100| is the distance from x to 100. The absolute value ensures the distance is never negative. We want this distance to be 25 because after traveling 25 cm, the switch is turned, and the train goes the other way.

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3 years ago
Lowest fraction using common term<br><br> 28/35
rjkz [21]
28/7=4
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4/5
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11111nata11111 [884]
The first one is 4/3

We can solve by,

{x}^{2} \times 180 = 320

x = \frac{4}{3}

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~~

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Idk how to explain...

~~

The third one is a 6 - gon therefore cannot be C or D.

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A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)
klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

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= 330.45 - 109.72

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Answer: 221

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choli [55]
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2x-6=0

2x=6

x=3

So the vertical asymptote is the vertical line x=3
3 0
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