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kipiarov [429]
3 years ago
7

Solve the equation 1/3m+6m-9/3m=3m-3/4m

Mathematics
1 answer:
vekshin13 years ago
3 0
M
=
0

O
r

m
=
23
15

Explanation:
1
3
m
+
6
m
−
9
3
m
=
3
m
−
3
4
m



⇒
1
+
6
m
−
9
3
m
=
3
m
−
3
4
m





⇒
−
8
+
6
m
3
m
=
3
m
−
3
4
m





⇒
(
−
8
+
6
m
)
×
4
m
=
(
3
m
−
3
)
×
3
m





⇒
−
32
m
+
24
m
2
=
9
m
2
−
9
m





⇒
−
32
m
+
24
m
2
−
9
m
2
+
9
m
=
0





⇒
15
m
2
−
23
m
=
0





⇒
m
(
15
m
−
23
)
=
0



m
=
0



Or


15
m
−
23
=
0
⇒
15
m
=
23
⇒
m
=
23
15
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<span>The function can be described as

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then </span><span> (s ∘ b)(p) would be
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irakobra [83]

Solving  ln(2x)+ln(2)=0 we get, x=\frac{1}{4}

Step-by-step explanation:

We need to solve: ln(2x)+ln(2)=0

Solving:

ln(2x)+ln(2)=0

Adding -ln(2) on both sides:

ln(2x)+ln(2)-ln(2)=0-ln(2)

ln(2x)=-ln(2)

Using logarithmic rule: if log_a b =c\,\,then\,\, b=a^c

So,

2x=e^{-ln(2)}

Simplifying:

2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}

So, Solving  ln(2x)+ln(2)=0 we get, x=\frac{1}{4}

Keywords: Logarithms

Learn more about Logarithms at:

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AysviL [449]

Answer:

(B)21+3a

Step-by-step explanation:

An expression is said to be distributive when:

(a+b)c=a \cdot c+b \cdot c

Given the algebraic expression: (7 + a)3

Applying the distributive property

(7 + a)3 = 7 \cdot 3+a \cdot 3\\=21+3a

An equivalent expression is 21+3a.

The correct option is B

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