If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?
1 answer:
Answer:
The complete part of the question is ; In the circuit in the figure, (Figure 1)a 20-ohm resistor sits inside 110 g of pure water that is surrounded by insulating Styrofoam. If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?
Use 4190J/kg⋅C∘ as the heat capacity of water, and express your answer in seconds using three significant figures.
answer = time taken = 1099.24secs
Explanation:
Tthe detailed calculation is as shown in the attachment.
The principle applied is the resolution of resistance of circuit in series and in parralel and then finding the equivlaent resistance.
Use the ohm's law equation to find the current in the circuit.
Use the Power generated
From the specific heat capacity equation to get the time duration.
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Answer:
The compound amount is $303.03 .
Explanation:
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Principle amount = $1100
Rate of the interest compounded semiannually :
= R = 9% = 0.09
Number of times interest compounded, n =
(semi means two times in a year)
Time period = T = 14
The compound amount is $303.03 .