<u>Answer:</u> The correct answer is Option 1.
<u>Explanation:</u>
Neutralization reaction is defined as the reaction in which acid reacts with a base to produce a salt along with water.
Here, HCl is an acid and
is a base. When these two compounds react, the salt obtained is calcium chloride.
The equation for the above reaction is given by:
![2HCl(aq.)+Ca(OH)_2(aq.)\rightarrow CaCl_2(s)+2H_2O(l)](https://tex.z-dn.net/?f=2HCl%28aq.%29%2BCa%28OH%29_2%28aq.%29%5Crightarrow%20CaCl_2%28s%29%2B2H_2O%28l%29)
Hence, the correct answer is Option 1.
824 g NH3 (1 mol/17 g NH3) (4 mol NO/4mol NH3)
48.47 moles NO
A 1-liter bag of IV solution would contain how many cubic centimeters of fluid?
1000 cc
<span> Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl </span>
<span>or
Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl this the complete balanced equation
now remove spectator ions to get net ionic equation
so
</span>
<span>
2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3- 2NO3- 2H+ [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
</span>hope it helps
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃] = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.