If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?
1 answer:
Answer:
The complete part of the question is ; In the circuit in the figure, (Figure 1)a 20-ohm resistor sits inside 110 g of pure water that is surrounded by insulating Styrofoam. If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?
Use 4190J/kg⋅C∘ as the heat capacity of water, and express your answer in seconds using three significant figures.
answer = time taken = 1099.24secs
Explanation:
Tthe detailed calculation is as shown in the attachment.
The principle applied is the resolution of resistance of circuit in series and in parralel and then finding the equivlaent resistance.
Use the ohm's law equation to find the current in the circuit.
Use the Power generated
From the specific heat capacity equation to get the time duration.
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Answer: 281 hours
Explanation:-
1 electron carry charge=
1 mole of electrons contain= electrons
Thus 1 mole of electrons carry charge=
of electricity deposits 1 mole or 63.5 g of copper
0.0635 kg of copper is deposited by 193000 Coloumb
11.5 kg of copper is deposited by= Coloumb
where Q= quantity of electricity in coloumbs = 34952756 C
I = current in amperes = 34.5 A
t= time in seconds = ?
Thus it will take 281 hours to plate 11.5 kg of copper onto the cathode if the current passed through the cell is held constant at 34.5 A.