All categories

4 years ago

If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?

Chemistry

1 answer:

denpristay [2]4 years ago

7 0

Answer:

The complete part of the question is ; In the circuit in the figure, (Figure 1)a 20-ohm resistor sits inside 110 g of pure water that is surrounded by insulating Styrofoam. If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?

Use 4190J/kg⋅C∘ as the heat capacity of water, and express your answer in seconds using three significant figures.

answer = time taken = 1099.24secs

Explanation:

Tthe detailed calculation is as shown in the attachment.

The principle applied is the resolution of resistance of circuit in series and in parralel and then finding the equivlaent resistance.

Use the ohm's law equation to find the current in the circuit.

Use the Power generated

From the specific heat capacity equation to get the time duration.

You might be interested in

Silver chloride is virtually insoluble in water so that the reaction appears to go to completion. How many grams of solid NaCl m

masya89 [10]

Answer:

0.535 g

Explanation:

The reaction that takes place is:

NaCl + AgNO₃ → AgCl + NaNO₃

First we calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution, using the definition of molarity:

Molarity = moles / liters

moles = Molarity * liters

Converting 25.0 mL to L ⇒ 25.0 / 1000 = 0.025 L

moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃

Then we convert AgNO₃ moles into NaCl moles:

0.00915 mol AgNO₃ * $\frac{1molNaCl}{1molAgNO_3}$ = 0.00915 mol NaCl

Finally we convert NaCl moles into grams, using its molar mass:

0.00915 mol NaCl * 58.44 g/mol = 0.535 g

4 0

3 years ago

What is the name for Mg2PO3?

Nimfa-mama [501]

I honestly don’t even know

7 0

3 years ago

What does D represent?

yuradex [85]

Answer:

The energy of the reactants.

3 0

2 years ago

Need help ASAP Ahsb

MArishka [77]

A but not sure for 100%

8 0

3 years ago

Read 2 more answers

When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of

baherus [9]

When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3

5 0

3 years ago