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2 years ago

15

Maurice pulls on the end of a spring scale. He lets go of the end and observes the spring snap back into place. What force resto

res the spring to its original shape?
a. tension

b. elastic

c. drag

d. applied

2 answers:

Luba_88 [7]2 years ago

8 0

Answer:

Elastic Force

Explanation:

As we pull the spring from one of its end by some distance such that its length is stretched by some amount "x"

So here the restoring force on the spring is given as

$F = kx$

so here we know

k = coefficient of elasticity

x = change in the length of spring

So here the restoring force on the spring will be Elastic force which always act opposite to the direction of displacement of the spring

andreev551 [17]2 years ago

3 0

Elastic is the right answer.

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Answer is suspension.

Lets define all options.

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In suspension the solute does not dissolve in liquid. When placed on table for some time, it will settle down at the bottom of the beaker. We can separate particles of solute easily from solvent through filtration.

<h3>Colloid:</h3>

In colloid particles of solute does not dissolve in liquid neither it is settle down. It floats through the solvent. It cannot be separated by filtration.

<h3>Solution:</h3>

In solution the particles of solute dissolve in to the solvent. We cannot identify them as separate. We cannot separate them by filtration. Salt and water solution is an example of it. Evaporation is the technique that is required to separate them.

<h3>Compound:</h3>

In compound, the two elements combine to form a new thing. Resultant/ compound have new or different properties other than its ingredients.

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It's the Doppler Effect that "up and down sound."

I was on Yahoo--- Brainly doesn't have an option for Credientials or Site credit, so I'll just put this in the quotes:

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<span>And you should pay attention to the signs: </span>
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<span>Applying it to this case: </span>

<span>s_source.of.wave = ? (positive), speed of ambulance </span>
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2 years ago

Light takes 8 minutes to reach the Earth, and the speed of light is 3.0×10^8 m/s. a) What is the orbital speed of the Earth arou

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Answer:

(a) 28690 m/s (b) $2.46x10^{33}J$

Explanation:

The orbital speed is define as:

$v = \frac{2 \pi r}{T}$ (1)

Where r is the radius of the trajectory and T is the orbital period.

To determine the orbital speed of the Earth it is necessary to know the orbital period and the radius of the trajectory. That can be done by means of the Kepler's third law and average velocity equation.

The average velocity in a Uniform Rectilinear Motion is defined as:

$v = \frac{d}{t}$ (2)

Where v is the velocity, d is the covered distance and t is the time.

Equation 2 can be rewritten for d to get:

$d = vt$ (3)

In this case, v will be the speed of light and t, the 8 minutes that takes to reach the Earth.

The time will be converted to seconds so the units in equation 3 can match:

$8min . \frac{60s}{1min}$ ⇒ $480s$

$t = 480s$

Replacing all those values in equation 3 it is gotten:

$d = (3.0x10^{8}m/s)(480s)$

$d = 1.44x10^{11}m$

Kepler’s third law is defined as:

$T^{2} = r^{3}$

Where T is orbital period and r is the radius of the trajectory.

$T = \sqrt{r^{3}}$

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It is necessary to pass from meters to astronomical unit (AU), 1 AU is defined as the distance between the Earth and the Sun.

$T = \sqrt{1AU}$

$T = 1AU$

That can be expressed in units of years.

$T = 1AU . \frac{1year}{1AU}$

$T = 1year$

But there are 31536000 seconds in one year:

$T = 1year . \frac{31536000s}{1year}$

$T = 31536000s$

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$v = \frac{2 \pi (1.44x10^{11}m)}{(31536000s)}$

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The kinetic energy is defined as:

$E = \frac{1}{2}mv^{2}$ (4)

Notice that it is necessary to found the mass of the Earth, that can be done combining the Universal law of gravity and Newton's second law:

$F = \frac{GMm}{r^{2}}$

$ma = \frac{GMm}{r^{2}}$ (5)

M will be isolated in equation 5:

$M = \frac{r^{2}a}{G}$

Where r is the radius of the Earth ( $6.38x10^{6}m$ )

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$E = 2.46x10^{33}Kg.m^{2}/s^{2}$

$E = 2.46x10^{33}J$

<u>Hence, the kinetic energy of Earth is $2.46x10^{33}J$ .</u>

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