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Anit [1.1K]
3 years ago
7

*PLEASE ANSWER ASAP*

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

1. (-6, -6)  (-2, -4) (-2, -6)

Write under each set (+6)

2. F" (-6, 0)  G" (-2, 2)  H" (-2,0)

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Which is a correct classification for the triangle?
matrenka [14]
The correct answer is Right triangle
8 0
3 years ago
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What is the value of x?<br><br><br><br> Enter your answer in the box.
Inessa05 [86]

Answer:

Since the two angles are across from each other that tells us that they are equal in length, so we want to set them equal to each other

3x+50=6x-10, Now we want to solve it like a normal equation, get x by itself

First add 10 to each side

3x+50+10=6x-10+10

3x+60=6x

Now we want to subtract 3x from each side

3x-3x+60=6x-3x

60=3x

Now divide both sides by 3

60/3=3x/3

20=x

x=20

Hope this helps ;)

Step-by-step explanation:

7 0
3 years ago
A rhombus can belong to multiple categories. which catergories does this rhombus not belong to? Select the two correct answers.
amid [387]

Answer:

Im pretty sure its c and d

6 0
3 years ago
Considering only the values of <img src="https://tex.z-dn.net/?f=%5Cbeta" id="TexFormula1" title="\beta" alt="\beta" align="absm
morpeh [17]

\large\boxed{Answer:}

We will use trigonometric identities to solve this. I will use θ (theta) for the angle.

First of all, we know that cotθ = 1/tanθ. This is a trigonometric identity.

We can replace cotθ in the expression with 1/tanθ.

sin\theta tan\theta sec\theta \frac{1}{tan\theta}

Simplify: 1/tanθ * tanθ = tanθ/tanθ = 1

So now, we have:

sin\theta sec\theta

Next, we also know that secθ = 1/cosθ. This is another trigonometric identity.

We can replace secθ with 1/cosθ in our expression.

sin\theta \frac{1}{cos\theta}

Simplify:

\frac{sin\theta}{cos\theta}

Our third trigonometric identity that we will use is tanθ = sinθ/cosθ.

We can replace sinθ/cosθ with tanθ.

Now we have as our final answer:

\large\boxed{b.\ tan\theta}

Hope this helps!

7 0
3 years ago
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Which system of equations has no solution?
Firlakuza [10]

The system of equation 5x+5y=10 and 2x+2y=4 has no solution.

The system of equation 3x-6y=4 and -4x+8y=7 has no solution.

Step-by-step explanation:

The set of equations "which cannot be solved for X and Y values is said to have no solution".

Now, let's try to solve the following sets of equations for x and y values to find which system of equation has no solution.

<u>option 1:</u>

divide the 1st equation by 5,

the equation becomes x+y=2

divide the 2nd equation by 2,

the equation becomes x+y=2

Both the equations are same, it cannot be solved and has no solution.

<u>option 2:</u>

look for the least coefficients of x and y to make multiplication easy

so, the coefficients of x are 3 and 4.

multiply equation1 by 4

the 1st eqn becomes 12x-24y=16

multiply euation2 by 3

the 2nd eqn becomes -12x+24y=21

Try to solve these two equation for x and y values.

since they cannot be solved to x and y values, it has No solution

Similarly the options 3 and 4 is to be solved to find either it has solution or not.

After solving <u>option 3</u>, the solution is x=0 and y=3

After solving <u>option 4</u>, the solution is x=4 and y=-1

7 0
3 years ago
Read 2 more answers
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