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Setler [38]
3 years ago
12

Fiona works for an organization that needs concise data as well as detailed historical data for analysis from time to time. Whic

h data warehouse
will be best suited for Flona's organization?

data warehouse will be best suited for Fiona's organization because it provides both concise and detailed data.

HELP FAST PLZ 100 points!!!!!!!!!!!
Business
2 answers:
Rasek [7]3 years ago
8 0

Answer:

Refer below.

Explanation:

Time-Variant :

Historical data is kept in a data warehouse. For instance, one can recover documents from 3 months, a half year, a year, or even past data from a data warehouse. These varieties with an exchanges framework, where regularly just the most current record is kept.

Subject-Oriented :

A data warehouse focus on the displaying and investigation of data for leaders. In this manner, data warehouses regularly give a compact and clear view around a specific subject, for example, client, item, or deals, rather than the worldwide association's progressing activities. This is finished by barring data that are not valuable concerning the subject and including all data required by the clients to comprehend the subject.

hoa [83]3 years ago
7 0

Answer:

The correct answer is: Enterprise Data Warehouse.

Explanation:

A Data Warehouse is a database characterized by integrating information of one or more different sources to then be processed for analysis at fast speed.  There are three main types of Data Warehouse: <em>Enterprise Data Warehouse (EDW), Operational Data Store, </em>and <em>Data Mart</em>.

Enterprise Data Warehouse collects a greater number of information for different areas in a firm in a unified layout. Historical data from all the business units are stored and made available according to the permissions the user has within the company. The data is useful for analysis which is mainly reviewed by top executives.

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Answer:

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We have to calculate the present value of the projects at their return rate

<u>Project A</u>

Present value of the cash flow - investment = net present value

\frac{21,000}{(1.12)^{1} } = PV

\frac{49,000}{(1.12)^{2} } = PV

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<u>Project B</u>

Present value of the cash flow - investment = net present value

-70,000 + PV 15,000 + PV 18,000 + PV 41,000

\frac{15,000}{(1.135)^{1} } = PV

\frac{18,000}{(1.135)^{2} } = PV

\frac{41,000}{(1.135)^{3} } = PV

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kirza4 [7]

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Explanation:

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Suppose Stark Ltd. just issued a dividend of $2.24 per share on its common stock. The company paid dividends of $1.80, $1.98, $2
Sergeu [11.5K]

Answer:

Ans, The cost of the company’s cost of equity capital using the arithmetic average growth rate is 10.63% and using the geometric average of the growth rate is 10.60%

Explanation:

Hi, this is the equation we need to solve in order to find the company’s cost of equity capital.

r=\frac{Dividend}{Price} +g

As you can see, we almost have everything, the only problem here is "g", its growth rate, so let´s find "g" using the arithmetic average, but first, we need to find the growth rate for every period, the formula is

g=\frac{(FinalDividend-PastDividend}{PastDividend}

Therefore, we need to find 4 g´s, let´s call them g1, g2, g3 and g4:

g1=\frac{(1.98-1.80)}{1.80} =0.10

g2=\frac{(2.05-1.98)}{1.98} =0.0354

g3=\frac{(2.16-2.05)}{2.05} =0.0537

g4=\frac{(2.24-2.16)}{2.16} =0.0370

So the average is:

Average(g)=\frac{0.10+0.0354+0.0537+0.0370}{4} =0.0565

Therefore, the average growth rate is 5.65%

And the company’s cost of equity is:

r=\frac{2.24}{45} +0.0565=0.1063

so, if the average growth rate is found by using the arithmetic average is 10.63%.

Now, let´s find the geometric average

g(average)=\sqrt[4]{(1+0.10)(1+0.0354)(1+0.0537)(1+0.0370)} -1=0.0562

therefore, using the geometric average to find the growth rate, the company’s cost of equity is:

r=\frac{2.24}{45} +0.0562=0.1060

using the geometric average, the company’s cost of equity is 10.60%

Best of luck.

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