From the question,
Heat lost by zinc = heat gained by water in the Styrofoam cup.
c'm'(t₁-t₃) = cm(t₃-t₂).............. Equation 1
Where c' = specific heat capacity of zinc, m' = mass of zinc, t₁ = initial temperature of zinc, t₂ = initial temperature of water in the Styrofoam cup, t₃ = temperature of the mixture
Make c' the subject of the equation
c' = cm(t₃-t₂)/m'(t₁-t₃).............. Equation 2
given: m' = 11.98 g = 0.01198 kg, m = density of water×volume of water = (1×50) = 50 g = 0.05 kg, t₁ = 78.4°C, t₂ = 27°C, t₃ = 28.1°C
Constant: c = 4200 J/kg.K
Substitute these values into equation 2
c' = 0.05×4200(28.1-27)/[0.01198×(78.4-28.1)]
c' = 231/0.602594
c' = 383.34 J/kg.K
Explanation:19,2 or 0/4 or 5 or 40,4
To solve this problem it is necessary to apply the rules and concepts related to logarithmic operations.
From the definition of logarithm we know that,
In this way for the given example we have that a logarithm with base 10 expressed in the problem can be represented as,
We can express this also as,
By properties of the logarithms we know that the logarithm of a power of a number is equal to the product between the exponent of the power and the logarithm of the number.
So this can be expressed as
Since the definition of the base logarithm 10 of 10 is equal to 1 then
The value of the given logarithm is equal to 6
the dependent variable is the one that changes because the independent variable was changed. The dependent isn't intentionally manipulated
A denser substance will have a higher or larger mass in the same volume. Therfore benzene will be a denser liquid as the mass is bigger in the same volume compared to ethonal.
You can also work this out by using the density formula which is mass of the substance over the unit of volume.