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Firlakuza [10]
3 years ago
15

A 4 kg block slides down a rough inclined plane inclined at 30° 179009.GIF with the horizontal. Determine the coefficient of kin

etic friction between the block and the surface if the block has an acceleration of 1.2 m/s2.
Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0
F=ma
F= 4x1.2
F= 4.8 N

F= 4gsin30 - Friction
Friction= 19.6 - 4.8 N
Friction= 14.8 N

Friction= u x 4gcos30
14.8 / 4gcos30 = u
u= 0.43596...
u= 0.44

coefficient is 0.44
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Answer:

C. Dark Matter

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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

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b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

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3 years ago
Some help me on this please
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Answer:

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