The magnitude of the induced electric field is (RdB/dt)/4
The induced electric field is gotten from
-∫E.dl = dФ/dt where E = induced electric field, dl = path length vector, Ф = magnetic flux through cylindrical region = AB where A = area of magnetic flux = πR² where R = radius of cylindrical region and B = magnetic field.
So, -∫E.dl = dФ/dt
-∫E.dl = dAB/dt
-∫Edlcos0 = AdB/dt (where E.dl = Edlcos0 = Edl since E and dl are parallel to each other.)
So -∫Edl = πR²dB/dt
-E∫dl = πR²dB/dt (∫dl = 2πr since the integral is the circumference of the path)
-E(2πr) = πR²dB/dt (we integrate dl from r = 0 to 2R)
-E2π(2R - 0) = πR²dB/dt
-E4πR= πR²dB/dt
E = πR²dB/dt ÷ 4πR
E = -(RdB/dt)/4
So, the magnitude of the induced electric field is (RdB/dt)/4
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➢ 1. force = mass × <u>acceleration</u>
➢ 2. Since unit of weight = kg•m/s²
Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:
Making the spring constant 
the subject of the formula; we have:
Substituting our given values, we have:
The magnitude of the force that must be apply to the hold platform in this position is given by the formula :
F = 888.89 N
Hello!
The statement that <span>describes the solar feature shooting off into space labeled C is An envelope of plasma surrounding the Sun.
This is called the Solar Corona. It is the outmost layer of the Sun's atmosphere. The Corona is hotter than the visible surface of the Sun. (1 000 000 - 3 000 000 K). It is composed of Plasma (The fourth state of the matter, similar to the gaseous state, but with electrically charged particles). All structural details of the Solar Corona are derived from the Magnetic Field of the Sun.
Have a nice day!</span>
Diagram a shows you a plate tectonic not a boundary and diagram b shows you a convergent plate boundary because the plates are coming together and the oceanic plate is being subducted undneath the continental plate
