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3 years ago

The diagram below outlines the appeals path through a state court system.

Physics

2 answers:

Stella [2.4K]3 years ago

6 0

Answer:

Explanation:

it is state level and which state level claim of a claim court

dexar [7]3 years ago

4 0

Answer:

B sorry if im wrong

Explanation:

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Early cameras were little more than a box with a pinhole on the side opposite the film. (a) What angular resolution would you ex

ollegr [7]

Answer:

angular resolution = 0.07270° = 1.269 × $10^{-3}$ rad

greatest distance from the camera = 118.20 m = 0.118 km

Explanation:

given data

diameter = 0.50 mm = 0.5 × $10^{-3}$ m

distance apart = 15 cm = 15× $10^{-2}$ m

wavelength λ = 520 nm = 520 × $10^{-9}$ m

to find out

angular resolution and greatest distance from the camera

solution

first we expression here angular resolution that is

sin θ = $\frac{1.22* \lambda }{D}$ .......................1

put here value λ is wavelength and d is diameter

we get

sin θ = $\frac{1.22*520*10^{-9}}{0.5*10^{-3}}$

θ = 0.07270° = 1.269 × $10^{-3}$ rad

and

distance from camera is calculate here as

θ = $\frac{I}{r}$ .................2

I = $\frac{15*10^{-2}}{1.269*10^{-3}}$

I = 118.20 m = 0.118 km

3 0

3 years ago

A muon is traveling at 0.988

AlexFokin [52]

As per Einstein's relation of relativity

$m = \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}}$

here we know that

$m_0 = 207 m_e = 207 \times 9.11 \times 10^{-31} kg$

$m_0 = 1.88 \times 10^{-28} kg$

now here we know that

$v = 0.988 c$

now from above equation mass of the muon is given as

$m = \frac{1.88 \times 10^{-28}}{\sqrt{1 - 0.988^2}}$

$m = 1.22 \times 10^{-27} kg$

now for the momentum of muon we can use

$P = mv$

$P = 1.22 \times 10^{-27} \times 0.988(3 \times 10^8)$

$P = 3.62 \times 10^{-19} kg m/s$

so above is the momentum of muon

6 0

3 years ago

Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on th

Lapatulllka [165]

Answer:

Option A. 4 m

Explanation:

Please see attached photo for diagram.

In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.

Clockwise moment = X × 45

Anticlock wise moment = 3 × 60

Clockwise moment = Anticlock wise moment

X × 45 = 3 × 60

X × 45 = 180

Divide both side by 45

X = 180 / 45

X = 4 m

Thus, the student must sit at 4 m from the centre.

4 0

2 years ago

An apple fell off a tree and is traveling to the ground.

marshall27 [118]

Answer:

GRAVITYYYYY

HOPE THIS HELPS

7 0

3 years ago

Read 2 more answers

A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction

Nezavi [6.7K]

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

$F_{n}$ = Normal force on the block by the ramp

$f_{k}$ = kinetic frictional force

Force equation perpendicular to ramp surface is given as

$F_{n} = mg Cos65$

Kinetic frictional force is given as

$f_{k} = \mu F_{n}$

$f_{k} = \mu mg Cos65$

Force equation parallel to ramp surface is given as

$mg Sin65 - f_{k} = ma$

$mg Sin65 - \mu mg Cos65 = ma$

$g Sin65 - \mu g Cos65 = a$

$(9.8) Sin65 - (0.17) (9.8) Cos65 = a$

$a = 8.2$ m/s²

4 0

3 years ago