Answer:
angular resolution = 0.07270° = 1.269 ×
rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 ×
m
distance apart = 15 cm = 15×
m
wavelength λ = 520 nm = 520 ×
m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ =
.......................1
put here value λ is wavelength and d is diameter
we get
sin θ =
θ = 0.07270° = 1.269 ×
rad
and
distance from camera is calculate here as
θ =
.................2
I = 
I = 118.20 m = 0.118 km
As per Einstein's relation of relativity

here we know that


now here we know that

now from above equation mass of the muon is given as


now for the momentum of muon we can use



so above is the momentum of muon
Answer:
Option A. 4 m
Explanation:
Please see attached photo for diagram.
In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
Divide both side by 45
X = 180 / 45
X = 4 m
Thus, the student must sit at 4 m from the centre.
Answer:
8.2 m/s²
Explanation:
m = mass of the block
μ = Coefficient of kinetic friction = 0.17
= Normal force on the block by the ramp
= kinetic frictional force
Force equation perpendicular to ramp surface is given as

Kinetic frictional force is given as


Force equation parallel to ramp surface is given as




m/s²