Well, after 1 half life, depending on whatever the amount is, 50% of the original content and or remaining content will undergo decay, as it is unstable.
Original content - 200g
1 half life - 100 g
2 half life - 50 g
3 half life - 25 g
The correct solution would be D. 25 g.
Answer:
10% solution volume
=7.5 L
30% solution volume = 2.5 L
Explanation:
assume 10% solution volume is x
So 30% solution volume = 10-x
Required 15% solution= x volume of 10% solution+ (10-x) volume of 30% solution
0.15 * 10L= 0.1 x + (10- x)* 0.3
1.5= 0.1 x+ 3 -0.3 x
0.2 x= 1.5
x= 7.5
10% solution volume is x
=7.5 L
So 30% solution volume = 10-x = 10-7.5= 2.5 L
Basically, this problem tells you to convert micrometers (μm) to millimeters (mm). The prefixes are used as hints for their values. Micrometer is 10⁻⁶ of a meter, while millimeter is 10⁻³ of a meter. If you use dimensional analysis,
(1.430×10⁻³ μm)*(10⁻⁶ m/1 μm)*(1 mm/10⁻³ m) = 1.43×10⁻⁶ mm
Answer:
1. Increase in the temperature of the water
2. Increasing the surface area of the lithium
Explanation:
1. Increase in the temperature of the water
The activation energy for the lithium water reaction is +161 kJ/mol while the activation energy for the sodium is +109 kJ/mol, hence for increased reaction rate, the water temperature will be raised to enable more lithium atoms enter into reaction with the water molecules as their energy is increased lowering the activation energy required for the reaction.
2. Increasing the surface area of the lithium
As the lithium floats on the water, due to its low temperature and the heat evolved from the reaction of lithium with the cold water is below the melting point of lithium, the reaction rate can be increased by increasing the surface area of lithium sample by grinding so as to increase the number of lithium water reaction sites.
B
A mixture can be separated by a physical means because there is no chemical bond between the constituents