We are given the amount of Nitrogen gas and hydrogen gas reacted to form ammonia:
N2 = 19.25 grams
H2 = 11.35 grams
Set-up a balanced chemical equation:
N2 + 3H2 ==> 2NH3
The theoretical amount of ammonia that will be produced from the given amounts is:
First, we need to determine the limiting reactant to serve as our basis for calculation.
number of moles / stoichiometric ratio
N2 = 19.25 g/ 28 g/mol / 1 = 0.6875
H2 = 11.35 g/ 2 g/mol /3 = 1.89
The limiting reactant is N2.
0.6875 moles N2 * (2 NH3/ 1 N2) * 17 g/mol NH3
The amount of NH3 produced is 23.375 grams of ammonia. <span />
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