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alukav5142 [94]
3 years ago
14

A chemistry student needs 65.0g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, th

e student discovers that the density of methyl acetate is ·0.934gcm−3. Calculate the volume of methyl acetate the student should pour out. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Tanya [424]3 years ago
3 0

Answer:

                    Volume =  69.6 cm³

Explanation:

                     Density is defined as <u>mass per unit volume</u>. It is an intensive property which remains constant for particular substance and is independent of the amount of that substance. It is given as,

                                  Density  =  Mass ÷ Volume

Data Given;

                  Density  =  0.934 g/cm³

                  Mass  =  65.0 g  

                  Volume  =  ?

Formula Used;

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density  

Putting values,

                  Volume  =  65.0 g ÷ 0.934 g.cm⁻³

                  Volume =  69.6 cm³

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2 years ago
Acetic acid and ethanol react to form ethyl acetate and water, like this:
ladessa [460]

Answer:

1.) Option C is correct.

The rate of reverse reaction is greater than zero, but equal to the rate of the forward reaction.

2) Option B is correct.

The rate of reverse reaction is Greater than zero, but less than the rate of the forward reaction.

3) Option C is correct.

The rate of reverse reaction is Greater than zero, and equal to the rate of the forward reaction.

4) Option A is correct.

How much less C2H5CO2CH3 is in the flask when the system has again reached equilibrium? Zero.

Explanation:

HCH,CO2(aq) + C2H5OH(aq) ⇌ C2H,CO2CH3(aq) + H2O

1) Before the main product is removed from the reaction setup, the chemical reaction is at equilibrium.

Chemical equilibrium is a state of dynamic equilibrium such that the concentration of the reactants and the products do not always remain the same but the rate of forward reaction always matches the rate of backward reaction.

2) When 246. mmol of C2HCO2CH3 are removed from the reaction mixture....

And when one of the factors involved in chemical equilibrium changes, Le Chatellier's principle explains that the system then adjusts to remedy this change and takes time to go back to equilibrium again.

When one of the species involved in the chemical reaction at equilibrium, is removed from the reaction mixture, the rate of reaction begins to favour that side of the reaction until equilibrium is re-established.

So, when 246 mmol of one of the products is removed, the response is to cause the rate of forward reaction to be favoured to produce more of products as there are fewer, and the rate of reverse reaction at this moment becomes less than the rate of forward reaction.

3) The rate of the reverse reaction when the system has again reached equilibrium

Like I said in (2) above, the reaction remedies this change in concentration of one of the products until equilibrium is re-established and when chemical equilibrium is re-established the rate of forward reaction once again matches the rate of backward reaction.

4) How much less C2H5CO2CH3 is in the flask when the system has again reached equilibrium?

By the time equilibrium is re-established, the system goes back to how it all was and the concentration of C2H5CO2CH3 goes back to the same as it was at the start of the reaction.

Hope this Helps!!!

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3 years ago
How is helium different from other noble gases?
Slav-nsk [51]
Helium only possesses two valence electrons, while the other noble gasses posses eight
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3 years ago
One hundred cubic meters of carbon dioxide initially at 150 oC and 50 bar is to be isothermally compressed in a frictionless pis
gulaghasi [49]

Answer: hundred cubic meters of carbon dioxide initially at 150◦C and 50 bar is to beisothermally compressed in a frictionless piston-and-cylinder device to a final pressure of 300 bar.Calculatei The volume of the compressed gas.ii The work done to compress the gas.iii The heat flow on compression.assuming carbon dioxide(a) Is an ideal gas.(b) Obeys the principle of corresponding states of Sec. 6.6(c) Obeys the Peng-Robinson equation of state.SolutionWe haveT1= 150◦C,P1= 50 bar,T2= 150◦C,P2= 300 bar. (1 and 2 denote the initialand final conditions in this ’snapshot’ problem, respectively - we have sometimes called themt1andt2)(a) If CO2is an idea gas, we havePV=NRT.The number of moles can be calculated from theinitial conditions:N1=P 1 V 1 RT 1 = (6 × 10 6 Pa)(100 m 3 ) (8 . 314 J/(mol K))(150 + 273 K) = 142127 mol = 142 . 1 kmol i. Since we know N 1 = N 2 , T 2 , P 2 V 2 = N 2 RT 2 P 2 = (142127 mol)(8 . 314 J/(mol K))(150 + 273 K ) 30 × 10 6 Pa = 16 . 66 m 3 ii. Since there is no shaft work, and since the gas is isothermally compressed , we only have pressure-volume work: W = - Z V 2 V 1 PdV = - Z V 2 V 1 NRT V dV = - NRT ln V 2 V 1 W = - (142127 mol)(8 . 314 J/(mol K))(150 + 273 K ) ln 16 . 66 100 = 8 . 958 × 10 8 J iii. Energy balance (integral form) for the closed system is: U 2 - U 1 = Q + W Back from homework 2, for an ideal gas, stating from equation 6.2-21, dU = C V dT + " T ∂P ∂T V - P # dV reduces to: dU = C V dT However, the process is isothermal, so dT = 0 Which gives: dU = Δ U = 1 N Δ U Therefore 0 = Q + W → Q = - W Q = - 8 . 958 × 10 8 J 3

Image of page 3

Explanation:As revealed above, the stimuli connections are clearly stated

4 0
3 years ago
If the empirical formula for a compound is NO2 and the molecular mass is 230.05 g/mol, what is the molecular formula for the com
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Answer: \text{N}_{5}\text{O}_{10}

Explanation:

  • The atomic mass of nitrogen is 14.0067 g/mol.
  • The atomic mass of oxygen is 15.9994 g/mol.

This means the molecular mass of nitrogen dioxide is 14.0067+2(15.9994)=46.0055 g/mol.

Dividing this molecular mass of the compound we need to find, we get that

\frac{230.05}{46.0055} \approx 5.

So, the final answer is \boxed{\text{N}_{5}\text{O}_{10}}

5 0
2 years ago
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