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Serjik [45]
3 years ago
12

A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.

Chemistry
1 answer:
White raven [17]3 years ago
4 0

2200 mg of antibiotic

Explanation:

Given that 40 mg of antibiotic/kg of the bodyweight is given.

If patient is 55 kg then  the dose of antibiotic will be

if 40/1000000 is done then we can get antibiotic in kg/kg of the weight

= 0.00004 kg of antibiotic per kg

0.00004*55 ( to know how much 55 kg person will require)

= 0.0022 kg

This 0.0022 value will be converted to mg

0.0022*10^6

= 2200 mg of antibiotic will be given to a 55kg patient.

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sdas [7]

Answer:

Electromagnet creates electricity.

Explanation:

4 0
3 years ago
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The element carbon exists in several different forms. Pure carbon can be found in the form of diamonds, coal, and the graphite i
UNO [17]

Answer:

B) All carbon atoms have 6 neutrons.

Explanation:

The false statement from the given choices is that all carbon atoms have 6 neutrons.

There is a phenomenon called isotopy in chemistry.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

  • These atoms of elements are called isotopes.
  • Carbon atoms generally have proton number of 6 which is the same as the atomic number.
  • As with all atoms, the mass number or atomic mass equals the number of protons and neutrons.

For the isotopes of carbon, their number of neutrons differs.

 For example:

            <em>¹²₆C                           ¹³₆C                        ¹⁴₆C</em>

The number of neutrons differs in the above isotopes.

 Number of neutrons = mass number - atomic number;

    ¹²₆C  , number of neutrons  = 12 - 6  = 6

      ¹³₆C, number of neutrons  = 13 - 6  = 7

       ¹⁴₆C, number of neutrons = 14 - 6  = 8

Therefore, based on the concept of isotopy, all carbon atoms do not have 6 neutrons.

7 0
3 years ago
Calculate the equilibrium constant of the reaction below if the pressures are 1.0atm, 2.0 atm, and 1.0 atm respectively. PCl3 +
Makovka662 [10]

Answer:

K = 0.5

Explanation:

Based on the reaction:

PCl₃ + Cl₂ ⇄ PCl₅

The equilibrium constant, K, is defined as:

K = P PCl₅ / P PCl₃ * P Cl₂

<em>Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.</em>

<em />

As:

P PCl₅ = 1.0atm

P PCl₃ = 1.0atm

P Cl₂ = 2.0atm

K = 1.0atm / 1.0atm * 2.0atm

<h3>K = 0.5</h3>
7 0
2 years ago
What experiments did Lavoisier do?
VikaD [51]
He did experiments with combustion and gas's
8 0
3 years ago
In a 0.730 M solution, a weak acid is 12.5% dissociated. Calculate Ka of the acid.
Mamont248 [21]

Answer:

Approximately 1.30 \times 10^{-2}, assuming that this acid is monoprotic.

Explanation:

Assume that this acid is monoprotic. Let \rm HA denote this acid.

\rm HA \rightleftharpoons H^{+} + A^{-}.

Initial concentration of \rm HA without any dissociation:

[{\rm HA}] = 0.730\; \rm mol \cdot L^{-1}.

After 12.5\% of that was dissociated, the concentration of both \rm H^{+} and \rm A^{-} (conjugate base of this acid) would become:

12.5\% \times 0.730\; \rm mol \cdot L^{-1} = 0.09125\; \rm mol \cdot L^{-1}.

Concentration of \rm HA in the solution after dissociation:

(1 - 12.5\%) \times 0.730\; \rm mol \cdot L^{-1} = 0.63875\; \rm mol\cdot L^{-1}.

Let [{\rm HA}], [{\rm H}^{+}], and [{\rm A}^{-}] denote the concentration (in \rm mol \cdot L^{-1} or \rm M) of the corresponding species at equilibrium. Calculate the acid dissociation constant K_{\rm a} for \rm HA, under the assumption that this acid is monoprotic:

\begin{aligned}K_{\rm a} &= \frac{[{\rm H}^{+}] \cdot [{\rm A}^{-}]}{[{\rm HA}]} \\ &= \frac{(0.09125\; \rm mol \cdot L^{-1}) \times (0.09125\; \rm mol \cdot L^{-1})}{0.63875\; \rm mol \cdot L^{-1}}\\[0.5em]&\approx 1.30 \times 10^{-2} \end{aligned}.

5 0
3 years ago
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