Answer:
Numbers 4, 6, & 7 are correct
Explanation:
4- this allows the op amp to have zero voltage so that maximum voltage is transferred to output load.
6- this ensures that op amp doesn't cause loading in the original circuit, high input impedance would not deter the circuit from pulling current from it.
7- high difference between upper and lower frequencies.
Answer:
Bore = 7 cm
stroke = 6.36 cm
compression ratio = 10.007
Explanation:
Given data:
Cubic capacity of the engine, V = 245 cc
Clearance volume, v = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
V = ![\frac{\pi}{4}D^2L](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7DD%5E2L)
or
V = ![\frac{\pi}{4}\frac{D^3}{1.1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cfrac%7BD%5E3%7D%7B1.1%7D)
on substituting the values, we have
245 = ![\frac{\pi}{4}\frac{D^3}{1.1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cfrac%7BD%5E3%7D%7B1.1%7D)
or
D = 7.00 cm
Now,
we have
D/L = 1.1
thus,
L = D/1.1
L = 7/1.1
or
L= 6.36 cm
Now,
the compression ratio is given as:
![\textup{compression ratio}=\frac{V+v}{v}](https://tex.z-dn.net/?f=%5Ctextup%7Bcompression%20ratio%7D%3D%5Cfrac%7BV%2Bv%7D%7Bv%7D)
on substituting the values, we get
![\textup{compression ratio}=\frac{245+27.2}{27.2}](https://tex.z-dn.net/?f=%5Ctextup%7Bcompression%20ratio%7D%3D%5Cfrac%7B245%2B27.2%7D%7B27.2%7D)
or
Compression ratio = 10.007
Answer:
see explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
The attached files has the solved problem.
Answer:
Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37
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