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3 years ago

How many color are in da rainbow

Engineering

2 answers:

Juli2301 [7.4K]3 years ago

8 0

Answer:

The classic rainbow has 6 colours. However, I have heard it other ways. The classic is listed below, as well as one example of the various colour patterns used in rainbows.

Examples:

Classic: Red, Orange, Yellow, Green, Blue, Purple

Ex. 1: Red, Orange, Yellow, Green, Blue, Indigo, Violet

Good luck!!

abruzzese [7]3 years ago

5 0

Seven colors are in the rainbow haha

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CAN SOMEONE GIVE ME AND ANSWER AND EXPLANTION FOR ALL THESE QUESTIONS PLEASE, I AM STRUGGLING

-BARSIC- [3]

Answer:

13.) 44V

14.) 66V

15.) 9A

16.) 12V

Explanation:

Concepts you need to know:

1. Resistors in series can be combined by summing up their values.

2. The current always stays the same when the resistors are in series.

3. Ohms Law: $V = IR$

13.) We know that the resistors are in series so we can combine them into a single big resistor. We got R₄ = R₃+R₂+R₁ = 2+4+5 = 11Ω.

We also know that current is the same in a series of resistors, so there's 4A going through the entire circuit.

Using ohm's law, we can calculate V = IR = (4)(11) = 44V

14.) Same explanation as part (13). Except now the current is I=6A. All we have to do is to replace the previous I=4 to I=6.

V = IR = (6)(11) = 66V

15.) Again, we know that current is the same when resistors are in series. So if you can find the current through R1 then that's the same current throughout the entire circuit.

We're given E₁=18V, so...

I = V/R = E₁/R₁ = 18/2 = 9A

this means 9A will also flow through R₃.

16.) Same concept as part (15). We know that E₃=15V, so lets find the current.

I = V/R = E₃/R₃ = 15/5 = 3A

Since current is same throughout the circuit, I₁=3A as well. Use this to calculate the voltage through R₁.

V = IR = I₁R₁ = (3)(2) = 6V

6 0

3 years ago

Write the definition of a function printLarger, which has two int parameters and returns nothing. The function prints the larger

vredina [299]

Answer:

#include <iostream>
using namespace std;
void printLarger(int a, int b){
if(a > b){
cout<<a;
}else{
cout<<b;
}
}
int main()
{
printLarger(4, 5);
return 0;
}

Explanation:

The solution code is written in C++.

Firstly define a function printLarger that has two parameters, a and b with both of them are integer type (Line 5). In the function, create an if condition to check if a bigger than b, print a to terminal (Line 7-8). Otherwise print b (Line 9-10).

In the main program, test the function by passing 4 and 5 as arguments (Line 16) and we shall get 5 printed.

7 0

4 years ago

Using a forked rod, a 0.5-kg smooth peg P is forced to move along the vertical slotted path r = (0.5 θ) m, whereθ is in radians.

-BARSIC- [3]

Answer:

N_c = 3.03 N

F = 1.81 N

Explanation:

Given:

- The attachment missing from the question is given:

- The given expressions for the radial and θ direction of motion:

r = 0.5*θ

θ = 0.5*t^2 ...... (correction for the question)

- Mass of peg m = 0.5 kg

Find:

a) Determine the magnitude of the force of the rod on the peg at the instant t = 2 s.

b) Determine the magnitude of the normal force of the slot on the peg.

Solution:

- Determine the expressions for radial kinematics:

dr/dt = 0.5*dθ/dt

d^2r/dt^2 = 0.5*d^2θ/dt^2

- Similarly the expressions for θ direction kinematics:

dθ/dt = t

d^2θ/dt^2 = 1

- Evaluate each at time t = 2 s.

θ = 0.5*t^2 = 0.5*2^2 = 2 rad -----> 114.59°

r = 1 m , dr / dt = 1 m/s , d^2 r / dt^2 = 0.5 m/s^2

- Evaluate the angle ψ between radial and horizontal direction:

tan Ψ = r / (dr/dθ) = 1 / 0.5

Ψ = 63.43°

- Develop a free body diagram (attached) and the compute the radial and θ acceleration:

a_r = d^2r / dt^2 - r * dθ/dt

a_r = 0.5 - 1*(2)^2 = -3.5 m/s^2

a_θ = r * (d^2θ/dt^2) + 2 * (dr/dt) * (dθ/dt)

a_θ = 1(1) + 2*(1)*(2) = 5 m/s^2

- Using Newton's Second Law of motion to construct equations in both radial and θ directions as follows:

Radial direction: N_c * cos(26.57) - W*cos(24.59) = m*a_r

θ direction: F - N_c * sin(26.57) + W*sin(24.59) = m*a_θ

Where, F is the force on the peg by rod and N_c is the normal force on peg by the slot. W is the weight of the peg. Using radial equation:

N_c * cos(26.57) - 4.905*cos(24.59) = 0.5*-3.5

N_c = 3.03 N

F - 3.03 * sin(26.57) + 4.905*sin(24.59) = 0.5*5

F = 1.81 N

4 0

3 years ago

A 200-L tank (see Fig. P4.107) initially contains water at 100 kPa and a quality of 1%. Heat is transferred to the water, thereb

Tomtit [17]

Answer:

25.46 MJ

Explanation:

continuity : m3 - m1 = -me

Energy Equation: m3u3 - m1u1 = -meue + 1Q3

See the image attached (Well typed out format)

5 0

4 years ago

Imagine the arc of a football as it flies through the air. How does this motion illustrate classical mechanics?

BigorU [14]

Answer: Maybe A

Explanation:

7 0

1 year ago

Read 2 more answers

How many color are in da rainbow​

How many color are in da rainbow