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Solnce55 [7]
3 years ago
9

Find your acceleration from 8.3 m/s to 12.5 m/s in 1.24 seconds.

Physics
1 answer:
balu736 [363]3 years ago
4 0

The <u>average</u> acceleration for an object undergoing this change in velocity is

(12.5 m/s - 8.3 m/s) / (1.24 s) = (4.2 m/s) / (1.24 s) ≈ 3.4 m/s²

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The earth exerts the necessary centripetal force on an orbiting satellite to keep it moving in a circle at constant speed. Which
jenyasd209 [6]

Answer:

E) The centripetal force is always perpendicular to the velocity.

Explanation:

Due to gravity and inertia, the satellite follows a uniform circular motion. In this movement, the velocity is always tangent to the orbit and the centripetal force is directed towards the center. Therefore, there is no net acceleration in the same direction of velocity, which implies that it remains constant.

8 0
4 years ago
Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of
vovangra [49]

Answer:

0.7 m/s

Explanation:

velocity of first runner = 3.5 m/s

velocity of second runner = 4.20 m/s

Both the runner are running in the same direction

velocity of second runner with respect to first runner = velocity of second runner - velocity of first runner

velocity of second runner with respect to first runner = 4.20 - 3.5 = 0.7 m/s

5 0
4 years ago
Derive the velocity of an electron in a hydrogen atom using Bohr's model. The electron has a mass of m, charge of (-e) and an or
Ahat [919]

Answer:

v=\frac{Ze^2}{2 \epsilon_0\times n\times h}

v=\frac {2.185\times 10^6}{n}\ m/s

Explanation:

According to Bohr's Theory,

The force of attraction acting between the electron and the nucleus is equal to the centrifugal force acting on the electron.

Thus,

\frac{Ze^2}{4\pi \epsilon_0 r^2}=m_e\frac{v^2}{r} ......1

Where, Z is the atomic number or the number of protons

r is the atomic radius

v is the velocity of the electron

m_e is the mass of the electron

Also,

Accoriding to Bohr, the angular momentum is quantized. He states that the angular momemtum is equal to the integral multiple of \frac {h}{2\times \pi}.

m_e vr=n\times \frac {h}{2\times \pi} ....2

solving r from equation 2, we get that:

r=n\times \frac {h}{2\times \pi\times m_e v}

Putting in 1 , we get that:

v=\frac{Ze^2}{2 \epsilon_0\times n\times h}

Applying values for hydrogen atom,

Z = 1

Mass of the electron (m_e) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

\epsilon_0 = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

v=\frac {2.185\times 10^6}{n}\ m/s

4 0
4 years ago
louis Pasteur developed the germ theory of disease, which state that many diseases are caused by microorganismas. Had scientists
Olegator [25]
Sciencefndkdkdkckkfkkdfk
3 0
3 years ago
A 770-kg boulder is raised from a quarry 106 m deep by a long uniform chain having a mass of 575 kg . This chain is of uniform s
Bas_tet [7]

Answer:

(a) a_{y}= 1.931m/s^{2}

(b) t=10.478s

Explanation:

For Part(a)

Apply ∑Fy=ma

T-Mg=Ma_{y} \\

Solve for a

a_{y}=\frac{T-Mg}{M}=\frac{2.80mg-Mg}{M} \\a_{y}=\frac{(2.80*575kg-1345kg)}{1345kg}*(9.80m/s^{2} )\\a_{y}= 1.931m/s^{2}

For Part(b)

Assume the maximum acceleration (maximum tension upwards is greater than the weight of the chain+boulder)

As the given data

a_{y}=1.931m/s^{2}\\  y-y_{o}=106m\\v_{oy}=0

Using equation of simple motion

y-y_{o}=v_{oy}t+(1/2)a_{y}t^{2} \\t=\sqrt{\frac{2(y-y_{o})}{a_{y}} }\\ t=\sqrt{\frac{2(106m)}{1.931m/s^{2} } }\\t=10.478s

4 0
4 years ago
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