Answer: 0.4533mol/L
Explanation:
Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol
68g of CaCO3 dissolves in 1.5L of solution.
Xg of CaCO3 will dissolve in 1L i.e
Xg of CaCO3 = 68/1.5 = 45.33g/L
Molarity = Mass conc.(g/L) / molar Mass
Molarity = 45.33/100 = 0.4533mol/L
Answer:
The answer to your question is D. 25 grams.
Answer:
The three isomers having the molecular formula 
are drawn in the figure below.
Explanation:
<span>The strong bonds give graphite high boiling and melting points, while the weak bonds make graphite soft and flexible.</span>
Answer:
mol times or devided by molar volume
