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Natali [406]
3 years ago
10

Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such li

nes near their homes could pose health dangers.For a line that has current 180 A and a height of 8 m above the ground, what is the magnetic field does the line produce at the ground level?
Physics
1 answer:
lozanna [386]3 years ago
6 0

Answer: 4.50*10^-6T (0.00000450071T)

Explanation: A current carrying conductor has been knowing to generate a specific amount of magnetic field.

This is given by the Bio-savart law (mathematical).

The Bio-savart law is a mathematical equation that gives the value of strength of the magnetic field created by a current carrying conductor.

B=(Uo* I) /2πr

Where

B= strength of magnetic field

Uo = magnetic permeability in free space = 1.257 *10^-6

r = distance between current carrying conductor and any reference point.

By doing the neccesary algebra, we have

B=(1.257 *10^-6 * 180)/ (2 * 3.142 * 8)

B= 2.2626 *10^-4 / 50.2857

B=4.5 * 10^-6T (0.00000450071T)

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Científico que formuló 3 leyes de astronomía
s2008m [1.1K]

Answer:

El astrónomo alemán Johannes Kepler

Explanation:

Primera Ley:

Los planetas giran alrededor del Sol siguiendo una trayectoria elíptica. El Sol se sitúa en uno de los focos de la elipse.

La excentricidad e de una elipse es una medida de lo alejado que se encuentran los focos del centro.

Pues bien, la mayoría de las órbitas planetarias tienen un valor muy pequeño de excentricidad, es decir e ≈ 0. Esto significa que, a nivel práctico, pueden considerarse círculos descentrados.

Segunda Ley:

La recta que une el planeta con el Sol barre áreas iguales en tiempos iguales.Para que esto se cumpla, la velocidad del planeta debe aumentar a medida que se acerque al Sol. Esto sugiere la presencia de una fuerza que permite al Sol atraer los planetas, tal y como descubrió Newton años más tarde.

Tercera ley de Kepler:

La tercera ley, también conocida como armónica o de los periodos, relaciona los periodos de los planetas, es decir, lo que tardan en completar una vuelta alrededor del Sol, con sus radios medios.

Para un planeta dado, el cuadrado de su periodo orbital es proporcional al cubo de su distancia media al Sol.

4 0
3 years ago
In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the
Vedmedyk [2.9K]

Answer:

2.2 s

Explanation:

Hi!

Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by

x(t) = 23.1 m - \frac{1}{2}(9.8 m/s^2) t^2

We are looking for a time t for which x(t) = 0

0 = 23.1 m - (4.9 m/s^2) t^2

Solving for t:

t = \sqrt{\frac{23.1}{4.9}} s = 2.17124 s

Rounding at the first decimal:

t = 2.2 s

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3 years ago
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aksik [14]
A part of a motor vehicle
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3 years ago
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vazorg [7]

Yes, it possible to orient a current loop in a uniform magnetic field such that the loop will not tend to rotate.

The forces on opposing sides of the loop would be equal in magnitude and opposite in direction if the magnetic field is pointed perpendicular to the plane of the loop; yet, there will be no net torque produced on the loop. In a constant magnetic field, there is no torque experienced by a current loop. A current carrying loop in a homogeneous magnetic field will never exert any net magnetic force. In a constant magnetic field, there is no torque experienced by a current loop. Due to the zero torque on the loop in this position, the plane of the loop is parallel to the direction of the magnetic field.

To know more about uniform magnetic field refer to brainly.com/question/25655915

#SPJ4

5 0
2 years ago
For a solar eclipse to occur which of the following alignments must be necessary
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