Answer:
A rover uses 4GHz frequency to transmit a picture. The rover’s transmission power is 200W. Distance = 55*10^9m. The transmission antenna gain is 10,000 and the receiving antenna gain is 100,000. What is the received signal strength at the Earth’s station, in W (assume Pi = 3.14)?
= 31.5 db
Explanation:
Path loss = 20㏒₁₀(4πdf / c)
= 20㏒₁₀(d) + 20㏒₁₀(f) - 20㏒₁₀(4π / c)
= 20㏒₁₀(55 × 10⁹) + 20㏒₁₀(4000) - 147.5
= (20 × 77.4) + 20 × 3.6 - 147.5
= 154 + 72 - 147.5
= 78.5 DB
Received signal strength(power)
Pr = Pt + Gt + Gr - Lp dBW
= 20 + 40 + 50 - 78.5
= 31.5 db
Answer:
63°
that's my answer
but then I am sorry if I'm wrong
Explanation:
90-27 = 63°
For part of our orbit the northern half of Earth is tilted toward the Sun. This is summer in the northern hemisphere; there are longer periods of daylight, the Sun is higher in the sky, and the Sun's rays strike the surface more directly, giving us warmer temperatures
<span>Each laid 250 bricks but while Jake was still working, Josh was lounging in the shade. Josh has more power but that power was only on for 3 hours out of 4.5. Obviously Josh could get more done is less time as long as he keeps working. Jake will get the hang of it soon.</span>
