M = 4kg
F =8N
a..?
F =m.a
8 = 4.a
a = 2m/s^2
Given Information"
Kinectic energy = 6.5 MeV
magnetic field = B = 1.9 T
Period = T = 1 ms
Required Information"
Diameter = d = ?
Answer:
d = 38.6 cm
f = 1000
Explanation:
(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron?
The radius and hence the diameter of the largest orbit can be found by using
r = mv
/|q|B
Where q = 1.60x10⁻¹⁹ C and m = 1.67x10⁻²⁷ kg and v is the speed of the particle which can be found by using
v = √2K
/m
Where K is the kinetic energy in Joules.
1 eV is equal to 1.60x10⁻¹⁹ J
K = 6.5x10⁶*1.60x10⁻¹⁹ = 1.04x10⁻¹² J
v = √2*1.04x10⁻¹²
/1.67x10⁻²⁷
v = 35.29x10⁶ m/s
r = 1.67x10⁻²⁷*35.29x10⁶
/1.60x10⁻¹⁹*1.9
r = 0.193 m
d = 2r
d = 2*0.193 = 0.386
or d = 38.6 cm
(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?
The period T and frequency (number of rotations per second) are related as
f = 1/T
f = 1/0.001
f = 1000
Answer:
Distance
Explanation:
Work can be defined as the energy transferred to a physical object by exertion of a force on the object to cause a displacement of the object. Thus, work is typically done when a person or simple machine move an object over a distance through the application of a force.
Mathematically, work done is given by the formula;
Where,
W is the work done
F represents the force acting on a body.
d represents the distance covered by the body.
A dependent variable is the event expected to change when an independent variable is manipulated.
Hence, distance is the dependent variable because its value changes with respect to the amount of force exerted on an object.