1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
insens350 [35]
4 years ago
8

Jeff's body contains about 5.46 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells

and the rest is plasma. The density of blood cells is approximately 1125 kg/m3, and about 1% of the cells are white blood cells, the rest being red blood cells. The red blood cells are about 7.50????m across (modeled as spheres).
a. What is the mass of the blood mblood in Jeff's body?

mblood=________________________kg

b. Approximately how many blood cells (of both types) ????N are in Jeff's blood?

????= _______________ blood cells
Physics
2 answers:
barxatty [35]4 years ago
6 0

Answer:

a

The mass of blood is m= 5.7876kg

b

The number of blood cells is  N_t=1.04*10^{13}

Explanation:

From the question we are told that

         The volume of blood  is  V_b = 5.46 \ L = \frac{5.46}{1000} = 0.00546m^3

         The density of the blood is  \rho_b = 1060 kg/m^3

         % of blood  that is  cell is  = 45.0%

        % of the blood that is  plasma is  = 55.0%

        density of blood cell is  \rho_d = 1125kg/m^3

        % of cell that are white is  = 1%

        % of cell that is red is  = 99%

        The diameter of the red blood cell is  = 7.5 \mu m = 7.5*10^{-6}m

         The radius of the red blood cell is  = \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m

Generally the mass is mathematically  represented as

               m = \rho_b * V_b

Substituting value

            m = 1060 * 0.00546

               m= 5.7876kg

Mass of cell is m_c = 45% of m

                         = 0.45 * 5,7876

                         = 2.60442 kg

The volume of cells is V_c = \frac{m_c}{\rho_d}

                                      = \frac{2.60442}{1125}

                                      = 2.315 *10^{-3} m^3

The volume of white blood cell is V_w = 1% of volume of cells

                                                         = \frac{1}{100} * 2.315*10^{-3}

                                                       = 2.315*10^{-5}m^3

The volume of a single cell is V_s = 4 \pi r^3

                                                                        = 4*(3.142) * (3.75*10^{-6})^3

                                                                        = 2.21*10^{-16}m^3

The volume of red blood cells is V_r = V_c - V_w

                                                           =2.315*10^{-3} - 2.315*10^{-5}

                                                           = 2.29*10^{-3}m^3

The number of red blood cell is  = \frac{V_r}{V_s}

                                                     = \frac{2.29 *10^{-3}}{2.21*10^{-16}}

                                                    = 1.037*10^{13}

The Number of white blood cell is   =\frac{V_w}{V_s}

                                                          = \frac{2.315 * 10^{-5}}{2.21*10^{-16}}

                                                          = 1.04*10^{11}

The total number of blood cells is  N_t= 1.037*10^{13} + 1.04*10^{11}

                                                        N_t=1.04*10^{13}

fgiga [73]4 years ago
6 0

Answer:

a) The mass of the blood is 5.788 kg

b) The total cells is 1.041x10¹³cells

Explanation:

Given:

V = volume of blood = 5.46 L = 0.00546 m³

ρ = density of blood = 1060 kg/m³

a) The mass of the blood is equal:

\rho =\frac{m}{V} \\m=\rho V=1060*0.00546=5.788kg

b) mc = mass of cells = 45% of mass of blood

mc = 0.45 * 5.788 = 2.6046 kg

ρc = density of cells = 1125kg/m³

The volume of the cells:

V_{c} =\frac{m_{c} }{\rho _{c} } =\frac{2.6046}{1125} =0.0023m^{3}

Vwc = volume of white blood cells = 1% of volume of the cells

Vwc = 0.01 * 0.0023 = 2.3x10⁻⁵m³

The radius of the cell is:

r_{c} =\frac{7.5x10^{-6} }{2} =3.75x10^{-6} m

The volume of a single cell is:

V_{sc} =\frac{4\pi r^{3} }{3} =\frac{4\pi (3.75x10^{-6})^{3}  }{3} =2.209x10^{-16} m^{3}

The number of the red blood cells is:

N_{rc} =\frac{0.0023-2.3x10^{-5} }{2.209x10^{-16} } =1.031x10^{13} cells

The number of the white blood cells is:

N_{wc} =\frac{2.3x10^{-5} }{2.209x10^{-16} } =1.041x10^{11} cells

The total cells is:

Tc = 1.031x10¹³ + 1.041x10¹¹ = 1.041x10¹³cells

You might be interested in
Fat Albert (the TV show character) runs up the stairs on Monday. On Tuesday, he walks up the same set of stairs. Which day did h
lys-0071 [83]

Answer:

Tuesday bc instead of running he/she was walking bc he/she might not have as much energy

Explanation:

8 0
3 years ago
A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the
Sindrei [870]

Answer:

Explanation:

How long does the football need to rise?

4.70/3 = 2.35 s

What height will the football reach?

h = ½(9.81)2.35² = 27.1 m

With what speed does the punter need to kick the football?

vy = g•t = 9.81(2.35) = 23.1 m/s

vx = d/t = 56.0/4.70 = 11.9 m/s

v = √(vx²+vy²) = 26.0 m/s

At what angle (θ), with the horizontal, does the punter need to kick the football?

θ = arctan(vy/vx) = 62.7°

3 0
2 years ago
3) show thal escape veloerty ve where symbols have their usual meaning?​
murzikaleks [220]

Answer:

v = \sqrt{\frac{2GM}{r} }

The formula for escape velocity where:

G - Gravitational constant (9.81 etc.)

M - the mass of the object the escape should be made from

r - distance to the centre of that mass

8 0
3 years ago
The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days). Determine the average angular velocity (in
lubasha [3.4K]

Answer:

Given that

The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days)

a)

When earth spins on its axis

We know that earth take 1 day to complete one revolution around its own axis.

T= 1 day = 24 hr = 24 x 3600 s

T=86400 s

We know that

T=2π/ω

ω= 2π/T

ω= 2π/86400

ω=7.27 x 10⁻5 rad/s

b)

When earth revolve around earth

T =365 1/4 days = 365.25 days

T= 365.24 x 86400 s

T=31557600

We know that

T=2π/ω

ω= 2π/T

ω= 2π/31557600

ω=1.99 x 10⁻⁷ rad/s

8 0
3 years ago
Read 2 more answers
What type of pipe wrenches are designed for turning and holding where marrying is not objectionable?
timurjin [86]
The type of pipe wrenches <span>that </span>are<span> designed for turning and holding where marrying is not objectionable is called the chain </span>wrench.<span> This tool has two serrated that are adjusted to grip the pipe. This is very useful for those objects where marrying is not objectionable since this can be adjusted for that purpose. </span>
3 0
3 years ago
Other questions:
  • Which pair of sentences is describing the same velocity? A car is parked. A car is moving in circles. A bus drives 40 miles per
    9·2 answers
  • Yesenia wants to bake cookies in her electric oven. The oven will transform electrical energy into ________ energy
    6·2 answers
  • A point charge is placed 100 m from a 6 uC charge generating an electric field. What is the
    7·1 answer
  • Why might political parties prefer closed primaries to open primaries
    11·1 answer
  • What type of force are you exerting when you lie on a bed
    10·1 answer
  • The critical angle for refraction from glass to air is 30° and that from water to air is 37°.Find the critical angle for refract
    7·1 answer
  • A plece of titanium has a mass of 67.5g and a volume of 15cm<br> What is the density?
    13·1 answer
  • HI, I really need help with this assignment for Physics:
    15·1 answer
  • A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
    5·1 answer
  • If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!