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9966 [12]
3 years ago
10

on june 21 some earth locations have 24 hours of daylight these locations are all between the latitudes of

Physics
1 answer:
andrew-mc [135]3 years ago
4 0

66° N and 90° N

the area of the artic circle in the northern hemisphere

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Kim took 5 hours to complete a journey with an average speed
monitta

Answer:110

Explanation:

6 0
3 years ago
Which of the following is the largest unit?<br> Hectogram<br> Dekagram<br> Decigram<br> Microgram
MAXImum [283]

Answer:

So far it seems that hectogram us the largest unit.

Dekagram is a metric unit of mass or weight, equal to 10 grams.

Hectogram is a metric unit of mass equal to 100 grams.

Decigram is  a metric unit of mass and weight equal to ¹/₁₀ gram.

Microgram is a metric unit of mass equal to one millionth of a gram.

8 0
3 years ago
A ball is thrown at a 60.0° angle above the horizontal across level ground. It is released from a
yawa3891 [41]
Write out what you have which is:
initial velocity 
final velocity 
Y distance 
degree

You do not have :
a
X distance 
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from what you have you can plug into your formulas to get time.
6 0
4 years ago
Why is it important for engineers to design bumper cars safely
rosijanka [135]

Answer:

Cars have bumpers designed to protect the body of the car from minor damage during low-speed collisions. ... They will use the engineering design process to design and build bumpers to protect the main parts of their car from damage, and use their knowledge of Newton's third law to explain what they observe.

Explanation:

3 0
3 years ago
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Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau
Tamiku [17]

Answer:

7.0\cdot 10^{-13}C

Explanation:

The magnitude of the electrostatic force between two charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

The force is attractive if the charges have opposite sign and repulsive if the charges have same sign.

In this problem, we have:

r=0.070 cm =7\cdot 10^{-4} m is the distance between the charges

q_1=q_2=q since the charges are identical

F=9.0\cdot 10^{-9}N is the force between the charges

Re-arranging the equation and solving for q, we find the charge on each drop:

F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(9.0\cdot 10^{-9})(7\cdot 10^{-4})^2}{8.99\cdot 10^9}}=7.0\cdot 10^{-13}C

8 0
3 years ago
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