Answer:
Relative density = 0.545
Degree of saturation = 24.77%
Explanation:
Data provided in the question:
Water content, w = 5%
Bulk unit weight = 18.0 kN/m³
Void ratio in the densest state, 
= 0.51
Void ratio in the loosest state, 
= 0.87
Now,
Dry density, 
= 17.14 kN/m³
Also,
here, G = Specific gravity = 2.7 for sand
or
e = 0.545
Relative density = 
= 
= 0.902
Also,
Se = wG
here,
S is the degree of saturation
therefore,
S(0.545) = (0.05)()2.7
or
S = 0.2477
or
S = 0.2477 × 100% = 24.77%
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Answer:
E=2 G(1+2μ)
Explanation:
Isotropic material :
Those material have same property in all direction is known as isotropic material.
Homogeneous material :
Those material have same property through out the volume is known as homogeneous material.
Relationship between Poisson ratio ,young modulus and shear modulus:
E=2 G(1+2μ)
Relationship between Poisson ratio ,bulk modulus and shear modulus:
E=2 K(1-μ)
Where
E is young modulus.
G is shear modulus.
μ is Poisson ratio.
Answer:
The dept of the water needed is 26.11m
Explanation:
Given the following parameters:
Length of the pipe = 
Diameter of the pipe = 
Volumetric flow rate 
Knowing that:
Volumetric flowrate 
==> 
*Knowing that 
==> 
==> 
Hence, the dept of water needed to produce a volumetric flow rate of is 26.11m.
Explanation:
D the answer is D and anyone can answer this Question
