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SOVA2 [1]
3 years ago
9

What determines the depth of the foundation excavation

Engineering
2 answers:
WARRIOR [948]3 years ago
7 0

Answer:

The required depth of any foundation can depend on several factors: Soil bearing capacity. This determines how much load (weight or force) the existing soil can withstand. Soil type.

Explanation:

Klio2033 [76]3 years ago
6 0
They determine based on ground movement studies in that area
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Independent auto lots usually have ____ finance rates than dealerships
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Independent auto lots usually have <u>higher</u> finance rates than dealerships

<u>Explanation:</u>

The finance rates that are charged by the dealers are lower than the finance charges that are charged by the independent auto. In case if you are getting financed through dealerships, you can also negotiate with them to charge finance rates and lower the charges of the finance.

But this negotiation and lowering of the finance rates is not possible with the independent auto lots and thus they charge higher rates compared to the dealerships.

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In poor weather, you should _______ your following distance.
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In poor weather, you should <u>double</u> your following distance.

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True or False: The differential lock in an AWD-equipped vehicle can be used at any time.
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the answer would be false

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Read 2 more answers
Calculate the viscosity(dynamic) and kinematic viscosity of airwhen
nikitadnepr [17]

Answer:

(a) dynamic viscosity = 1.812\times 10^{-5}Pa-sec

(b) kinematic viscosity = 1.4732\times 10^{-5}m^2/sec

Explanation:

We have given temperature T = 288.15 K

Density d=1.23kg/m^3

According to Sutherland's Formula  dynamic viscosity is given by

{\mu} = {\mu}_0 \frac {T_0+C} {T + C} \left (\frac {T} {T_0} \right )^{3/2}, here

μ = dynamic viscosity in (Pa·s) at input temperature T,

\mu _0= reference viscosity in(Pa·s) at reference temperature T0,

T = input temperature in kelvin,

T_0 = reference temperature in kelvin,

C = Sutherland's constant for the gaseous material in question here C =120

\mu _0=4\pi \times 10^{-7}

T_0 = 291.15

\mu =4\pi \times 10^{-7}\times \frac{291.15+120}{285.15+120}\times \left ( \frac{288.15}{291.15} \right )^{\frac{3}{2}}=1.812\times 10^{-5}Pa-swhen T = 288.15 K

For kinematic viscosity :

\nu = \frac {\mu} {\rho}

kinemic\ viscosity=\frac{1.812\times 10^{-5}}{1.23}=1.4732\times 10^{-5}m^2/sec

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3 years ago
What can be the main disadvantage of pulse amplitude modulation?​
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Answer:

transmission bandwidth required is very large.

Explanation:

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2 years ago
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