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2 years ago

If 0.35 m of ammonia solution has a ph of 9.15, what is the h+ concentration of the solution?

1 answer:

5 0

The pH of the substance is calculated through the equation,
pH = -log[H⁺]
This means that the pH of a certain substance is the negative log of the concentration of the H⁺ ions. In this item, we are given with the pH of the substance.

Substituting the known value of pH,
9.15 = -log[H⁺]

The value of [H⁺] is 7.08 x 10⁻¹⁰.

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In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False

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Answer:

false

Explanation:

As we know that in sodium-potassium pump .

sodium potassium move 3Na+ outside the cells

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so that we can say that given statement is false

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2 years ago

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Answer:

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2 years ago

The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

Rina8888 [55]

Answer: The expression of $K_b$ is written below.

Explanation:

We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.

It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.

The chemical equation for the reaction of trimethylamine in water follows:

$(CH_3)_3N+H_2O\rightleftharpoons (CH_3)_3NH^++OH^-$

The expression of $K_b$ for above equation follows:

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Hence, the expression of $K_b$ is written above.

5 0

3 years ago

a solution of sodium hydroxide, 0.0500 M, is used to titrate a 15.00 mL sample of hydrochloric acid to the endpoint. The initial

Akimi4 [234]

Answer:

The answer to your question is Molarity = 0.0708

Explanation:

Data

NaOH 0.05 M Volume 1 = 3.87 ml Volume 2 = 25.11 ml

HCl 15 ml

Process

1.- Find the volume used of NaOH

25.11 - 3.87 = 21.24 ml = 0.02124 l

2.- Write the balanced equation of the reaction

NaOH + HCl ⇒ NaCl + H₂O

3.- Calculate the moles of NaOH in the solution

Molarity = $\frac{moles}{volume}$

moles = Molarity x volume

moles = 0.05 x 0.02124

moles = 0.001062

4.- From the reaction we know that NaOH and HCl react in a proportion 1:1.

1 mol of NaOH ------------- 1 mol of HCl

0.001062 moles of NaOH ------------ x

x = (0.001062 x 1) / 1

x = 0.001062 moles of HCl

5.- Find the molarity of HCl

Molarity = $\frac{0.001062}{0.015}$

Molarity = 0.0708

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2 years ago

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Atoms are now not indivisible and and the elements are identical

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3 years ago