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3 years ago

If 0.35 m of ammonia solution has a ph of 9.15, what is the h+ concentration of the solution?

1 answer:

5 0

The pH of the substance is calculated through the equation,
pH = -log[H⁺]
This means that the pH of a certain substance is the negative log of the concentration of the H⁺ ions. In this item, we are given with the pH of the substance.

Substituting the known value of pH,
9.15 = -log[H⁺]

<em>The value of [H⁺] is 7.08 x 10⁻¹⁰.</em>

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The complete orbital notation diagram of an atom is shown.

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Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

l (n-1) name of orbital shape of orbital

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J = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

2s² the l value is 0, 1 and the electron can be in the s or p orbitals

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3 years ago

Calculate the volume, in milliliters, for the following:

fredd [130]

Answer: The volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

As given moles of $NaNO_{3}$ are 0.850 mol and molarity of $NaNO_{3}$ solution is 0.5 M. Hence, its volume is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL$

Therefore, the volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol$

So, volume for LiOH solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL$

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

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3 years ago

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The answer is the last option.

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3 years ago