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djverab [1.8K]
3 years ago
6

If 0.35 m of ammonia solution has a ph of 9.15, what is the h+ concentration of the solution?

Chemistry
1 answer:
Rasek [7]3 years ago
5 0
The pH of the substance is calculated through the equation,
                   pH = -log[H⁺]
This means that the pH of a certain substance is the negative log of the concentration of the H⁺ ions. In this item, we are given with the pH of the substance. 

Substituting the known value of pH,
              9.15 = -log[H⁺]

<em>The value of [H⁺] is 7.08 x 10⁻¹⁰.</em>
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Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

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3 years ago
Which of the following pairs of substances form a buffer system for human blood?
ss7ja [257]

Answer:

d. Because those chemicals are easily made when CO2 reacts with water, forming H2CO3 (via carbonic anhydrase

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3 years ago
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blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

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Answer:

pen

Explanation:

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