1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slavikrds [6]
3 years ago
10

Any two application of gravity

Physics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

Well the definition of an application is the act of putting to a special use or purpose so lam assuming that you want specific uses that scientists make of gravity in their work.

Well our first application has helped us to send satellites around the solar system with what Nasa calls gravity assist. Using a particular planets gravity to slingshot a satellite to another destination. Look it up.

The next application much simpler but here on Earth. There are many hydro-electric power stations in use all over the world. Water is stored at a high level and released falling 100s of metres to a turbine where it generates electricity.

Hope that helps.

Explanation:

You might be interested in
Cómo se complementan la ciencia y la tecnología​
Andreyy89

Answer:

La ciencia y la tecnología se complementan porque la tecnología necesita que la ciencia sea una cosa y la ciencia se usa en tecnología

Explanation:

4 0
3 years ago
A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of
Dominik [7]

Answer:

The centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s²

Explanation:

Given;

distance traveled in the given time = 200 m

time to cover the distance, t = 29.6 s

speed of the runner, v = d / t

v = 200 / 29.6

v = 6.757 m/s

The centripetal acceleration of the runner is given by;

a_c = \frac{V^2}{r}

where;

r is the radius of the circular arc, given as 50 m

Substitute the givens;

a_c = \frac{V^2}{r}\\\\a_c = \frac{(6.757)^2}{50}\\\\a_c = 0.91 \ m/s^2

Therefore, the centripetal acceleration of the runner as he runs the curved portion of the track is 0.91 m/s².

5 0
3 years ago
Please help me!
Kay [80]

Answer:

A black body radiator is an idealized body that absorbs all incoming electromagnetic radiation (thus the name of "black body").

A black body radiator is an object that has a lot of thermal energy, and it irradiates its thermal energy in the form of black body radiation (thermal radiation emitted by a black body).

a) Then, we could go to the trivial case of a mirror, a mirror is a poor blackbody radiator because a mirror reflects most of the incoming electromagnetic radiation, thus, a mirror is a really bad approximation for a black body, then a mirror is a poor black body radiator.

b) Any electromagnetic wave is a light wave (there exists "light" that we can not see). A black body radiator irradiates energy, and this radiation is in the form of electromagnetic waves, which are in essence, light waves.

7 0
3 years ago
The satellite s travels around the earth in a circular path with a constant speed of 20 mm>h. If the acceleration is 2.5 m&gt
Zanzabum

<u>Answer:</u>

The altitude of planet = 5989.198 km

<u>Explanation:</u>

    We know that centripetal acceleration, a = v^2/r, where v is the velocity and r is the radius. In this case both acceleration and velocity is given, so we can find radius of satellite.

    v = 20 Mm/hr = 20*10^6/3600 = 5555.56 m/s

    a = 2.5 m/s^2

 So,  2.5 = 5555.56^2/r\\ \\ r = 12345698.77 m = 12345.698km

 We have diameter of earth = 12713 km

        Radius of earth = 12713/2 = 6356.5 km

   The altitude of planet = Radius of planet - radius of earth

                                         = 12345.698 - 6356.5

                                         = 5989.198 km

8 0
3 years ago
An artillery shell has a mass of 55 kg. The shell is fired from the muzzle of the gun
Evgen [1.6K]

The average force on the shell while it is in the gun barrel is 10,869,833.33N.

<h3>HOW TO CALCULATE FORCE?</h3>

Force applied on an object can be calculated by multiplying the mass of the object by its acceleration.

However, the acceleration needs to be calculated by using the following equation:

v² - u² = 2as

Where;

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • s = distance

770² - 0² = 2 (a)(1.5)

592900 = 3a

a = 197633.3m/s²

Force = 55kg × 197633.3m/s²

Force = 10,869,833.33N

Therefore, the average force on the shell while it is in the gun barrel is 10,869,833.33N.

Learn more about force at: brainly.com/question/26115859

4 0
2 years ago
Other questions:
  • A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward
    9·1 answer
  • Two students play tug of war. Jack pulls East with a force of 82 Newtons while Tony pulls west with a force of 96 Newtons. Which
    5·2 answers
  • A child is sitting in a sled at the top of a snowy hill. Which statement is true regarding the position of the child?
    6·1 answer
  • A(n) 14 g bullet is fired into a(n) 121 g block of wood at rest on a horizontal surface and stays inside. After impact, the bloc
    8·1 answer
  • Which does not provide the energy to spin a turbine?
    9·2 answers
  • What does the word 'latent' means​
    8·1 answer
  • When we throw an arrow by streching the string of a bow , how does the energy change take place ?​
    5·2 answers
  • Vanessa made a list comparing the differences between the outer coverings in plants and animals, but she made a mistake. Read th
    14·1 answer
  • Convert 14 mg to kg ....<br>​
    15·2 answers
  • A small water droplet in a mist of air is approximated as being a sphere of diameter 1.25 mil. Calculate the terminal velocity a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!