Move the decimal point to:
Left : (if the exponent of ten is a negative number -) ... OUR CASE HERE (-2)
or to
Right : (if the exponent is positive +).
You should move the point as many times as the exponent indicates.
Do not write the power of ten anymore.
So, standard form is:
Two points to the left {Exponent of Ten is Negative (-2)}
0.059 ... (without the 10)
The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
<h3>What is flow rate?:</h3>
This is the volume of fluid flowing in a vessel per unit time.
First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.
Using,
- V = F'm................ Equation 1
Where:
- V = Volume of the blood
- F' = Flow rate
- m = mass of blood.
For the Adult,
Given:
Substitute these values into equation 1
For the child,
Given:
Substitute these values into equation 1 also
The amount of blood that flows more through the adult than the child is
- A = 5250-1500
- A = 3750 ml.
Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.
Learn more about flow rate here: brainly.com/question/21630019
Answer:
R=3818Km
Explanation:
Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.
Since you travel 2π radians in 24H, the angle can be calculated as:
t being expressed in hours.
From the triangle formed by A,B and the center of the planet, we know that:
Solving for r, we get:
Answer:
b) 1.29 V
Explanation:
Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field
The expression for the potential difference is
Q = CV .................... Equation 1
Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.
Making V the subject of the equation,
V = Q/C................. Equation 2
Given: Q = 4.5 µC = 4.5×10⁻⁶ C, C = 3.5 µF = 3.5×10⁻⁶ F
Substituting into equation 2
V = 4.5×10⁻⁶ /3.5×10⁻⁶
V = 1.2857 V
V ≈ 1.29 V.
Hence the right option is b) 1.29 V
