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cestrela7 [59]
3 years ago
13

Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)

Physics
1 answer:
vaieri [72.5K]3 years ago
6 0

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A =  0.29 J

\mu =3716.35 J/mole

Explanation:

given data:

Kr  atomic number = 36

degree of freedom = 3

1) internal energy E = \frac{f}{2} n R T

                                = \frac{3}{2} *1*8.314*298 = 3716.35 j

2) cv = \frac{E}{T}

         = \frac{3716.35}{298} = 12.47 J/K

3) S = cv =\frac{E}{T} = 12.47 J/K

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole

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