Question

Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)

Answer 1

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A =  0.29 J

$\mu =3716.35 J/mole$

Explanation:

given data:

Kr  atomic number = 36

degree of freedom = 3

1) internal energy E = $\frac{f}{2} n R T$

                                = $\frac{3}{2} *1*8.314*298 = 3716.35 j$

2) $cv = \frac{E}{T}$

         $= \frac{3716.35}{298} = 12.47 J/K$

3) $S = cv =\frac{E}{T} = 12.47 J/K$

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)$chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole$