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3 years ago

Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)

Physics

1 answer:

vaieri [72.5K]3 years ago

6 0

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A = 0.29 J

$\mu =3716.35 J/mole$

Explanation:

given data:

Kr atomic number = 36

degree of freedom = 3

1) internal energy E = $\frac{f}{2} n R T$

= $\frac{3}{2} *1*8.314*298 = 3716.35 j$

2) $cv = \frac{E}{T}$

$= \frac{3716.35}{298} = 12.47 J/K$

3) $S = cv =\frac{E}{T} = 12.47 J/K$

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5) $chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole$

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3 years ago

A 10.0 cm object is 5.0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and th

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Let's use the mirror equation to solve the problem:
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For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for $d_i$ by using the numbers given in the text of the problem:
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3 years ago

Read 2 more answers

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.7 m tall window in 0.129 sec. From how high above th

vladimir1956 [14]

Answer:

h = 22.35 m

Explanation:

given,

initial speed of the rock,u = 0 m/s

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time taken to cross the window,t = 0.129 s

Speed of the rock when it crosses the window

$v = \dfrac{l}{t}$

$v = \dfrac{2.7}{0.129}$

v = 20.93 m/s

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v² = u² + 2 g h

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3 years ago

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Answer:

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3 years ago

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