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Mama L [17]
3 years ago
12

PLS HELP!!!

Chemistry
2 answers:
lions [1.4K]3 years ago
6 0
The answer is B) heat will flow from the water to the copper until they both reach the same temperature
AlladinOne [14]3 years ago
6 0

Answer:

Heat will flow from the water in the glass to the copper until both reach the same temperature.

Explanation:

If we consider a perfectly thermal insulation in the system with glass of water at higher temperature and piece of copper at lower temperature, then when the both come in contact with each other water will lose some heat and copper will gain that heat from water. The process will continue untill both reach the same temperature. One they will reach to same temperature we will not observe any heat change or temperature change between the two.

Heat change is a function of temperature difference.

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Specific heat and thermal Energy question. Will give brailiest. 30 points please answer!! ASAP
USPshnik [31]
What’s the question?
3 0
3 years ago
Read 2 more answers
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Triss [41]

Answer: because they take a lot of tie to form  

4 0
3 years ago
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At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)
sdas [7]

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

5 0
2 years ago
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
Consider this equilibrium reaction at 400 K. Br2(g)+Cl2(g)↽−−⇀2BrCl(g)Kc=7.0 If the composition of the reaction mixture at 400 K
Genrish500 [490]

Answer:

Q = 7.0

Q = kc. The reaction is in equilibrium

Explanation:

Based on the reaction:

Br₂ + Cl₂ ⇄ 2BrCl

Equilibrium constant of the reaction, kc, is the ratio of <em>equilibrium concentrations</em> products over reactants powered to its reaction coefficient:

Kc = [BrCl]² / [Br₂] [Cl₂] = 7.0

Now, reaction quotient, Q, is write as the same Kc but the concentrations are actual concentrations:

Q = [BrCl]² / [Br₂] [Cl₂]

Replacing:

Q = [0.00415M]² / [0.00366M] [0.000672M]

Q = 7.0

Now, as Q = Kc = 7.0, the reaction mixture is in equilibrium

4 0
3 years ago
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