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Mama L [17]
3 years ago
12

PLS HELP!!!

Chemistry
2 answers:
lions [1.4K]3 years ago
6 0
The answer is B) heat will flow from the water to the copper until they both reach the same temperature
AlladinOne [14]3 years ago
6 0

Answer:

Heat will flow from the water in the glass to the copper until both reach the same temperature.

Explanation:

If we consider a perfectly thermal insulation in the system with glass of water at higher temperature and piece of copper at lower temperature, then when the both come in contact with each other water will lose some heat and copper will gain that heat from water. The process will continue untill both reach the same temperature. One they will reach to same temperature we will not observe any heat change or temperature change between the two.

Heat change is a function of temperature difference.

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Answer:

i guess b maybe the answer

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Explain what happens to substances during a chemical change
Free_Kalibri [48]

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.

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A macromolecule made up of mainly carbon and hydrogen atoms that is primarily used for energy storage and in cell membranes.
Alex787 [66]
I believe the answer is glucose
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3 years ago
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Which step in the free-radical chlorination of methane do you expect to be the most exothermic? attempt this problem without loo
stiks02 [169]

The termination step of the free-radical chlorination of methane is the most stable one among all three steps.

The free-radical substitution reaction between chlorine and methane features three major steps:

Initiation, during which chlorine molecules undergo homolytic fission to produce chlorine free radicals. Ultraviolet radiations are typically applied to supply the energy required for breaking the chlorine-chlorine single bonds. The initiation step is thus <em>endothermic</em>.

Propagation, a process in which chlorine free radicals react with methane molecules and remove a hydrogen atom from the alkane to produce hydrogen chloride and an alkyl radical e.g., \cdot \text{CH}_3. The carbon-containing free radical would react with chlorine molecules to produce chloromethane and yet another chlorine free radical. This process can well repeat itself to chlorinate a significant number of methane molecules.

Termination. Free radicals combine to produce molecules. For example, two chlorine free radicals would combine to produce a chlorine molecule, whereas two alkyl free radicals would combine to produce an alkane with two-carbon atoms in its backbone.

Chemical processes that increase the stability of a substance reduces its chemical potential energy. Energy conserves, thus such processes would also release energy equal to the potential energy lost in quantity. Free radicals are unstable and- as seen in the propagation step- compete readily with neutral molecules for their electrons. The propagation step keeps the number of free radicals constant and is therefore more exothermic than the initiation step. The termination step reduces the number of free radicals, increase the stability of the system by the greatest extent, and is therefore the most exothermic step among the three.

3 0
3 years ago
Find the pH. What are the pH values for the following solutions? (a) 0.1 M HCl (b) 0.1 M NaOH (c) 0.05 M HCl (d) 0.05 M NaOH
slega [8]

Answer:

(a) pH=1

(b) pH=1.3

(c) pH=13

(d) pH=12.7

Explanation:

Hello,

In this case, we define the pH in terms of the concentration of hydronium ions as:

pH=-log([H^+])

Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:

(a)

[H^+]=[HCl]=0.1M

pH=-log(0.1)=1

(b)

[H^+]=[HCl]=0.05M

pH=-log(0.05)=1.3

Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:

[OH^-]=[NaOH]

pOH=-log([OH^-])

pH=14-pOH

Thus, we have:

(b)

pOH=-log(0.1)=1\\pH=14-1=13

(d)

pOH=-log(0.05)=1.3\\pH=14-1.3=12.7

Best regards.

5 0
3 years ago
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