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antoniya [11.8K]
3 years ago
9

Ramelteon is a hypnotic agent used in the treatment of insomnia: Considering the labeled drawing above, which of the highlighted

atoms has a delocalized lone pair? Select all that apply. 1 2 3 Identify the geometry of each atom (except for hydrogen atoms). All sp2-hybridized carbon atoms have geometry. All sp3-hybridized carbon atoms have geometry. The nitrogen atom has geometry. The oxygen atom of the C=O bond has geometry, and the other oxygen atom has geometry.
Chemistry
1 answer:
9966 [12]3 years ago
7 0

Answer:

1 and 2

Trigonal planar

Tetrahedral

Trigonal Planar

Linear

Bent ( v- shape)

Explanation:

The highlighted atoms has a delocalized lone pair - 1 and 2

All sp2-hybridized carbon atoms have geometry- Trigonal planar

All sp3-hybridized carbon atoms have geometry - Tetrahedral

The nitrogen atom has geometry - Trigonal Planar

The oxygen atom of the C=O bond has geometry - Linear

and the other oxygen atom has geometry - Bent ( v- shape)

P.S - The correct question is -

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son4ous [18]

Answer:

2nd one

Explanation:

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3 years ago
Explain why the law of conservation of energy can mean that we do not have unlimited sources of energy.
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3 years ago
A balloon full of air has a volume of 1.00L at a temperature of 23 °C. What is the balloon's volume at 33°C?
igomit [66]

Answer:

V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

V2= 1.03L

5 0
3 years ago
Suppose a gas starts with a volume of 4.52L, temperature of 23 C, and pressure of 102,00 Pa. If the volume changes to 4.83L and
ivanzaharov [21]

Answer:

The answer to your question is     P2 = 84.16 kPa

Explanation:

Data

Volume 1 = V1 = 4.52 L            Volume 2 = V2 = 4.83 l

Pressure 1 = P1 = 102 kPa        Pressure 2 = P2 = ?

Temperature 1 = T1 = 23°C      Temperature 2 = T2 = -12°C

Process

1.- Convert the temperature to °K

Temperature 1 = 23 + 273 = 296°K

Temperature 2 = -12 + 273 = 261°K

2.- Use the Combined Gas law to solve this problem

                  P1V1/T1 = P2V2/T2

-Solve for P2

                  P2 = P1V1T2 / T1V2

-Substitution

                  P2 = (102)(4.52)(261) / (296)(4.83)

-Simplification

                  P2 = 120331.44 / 1429.68

-Result

                  P2 = 84.16 kPa

8 0
3 years ago
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