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xeze [42]
3 years ago
15

Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were coole

d from 90.0oC to 30.0oC.
Chemistry
1 answer:
Over [174]3 years ago
6 0

Answer:

V₂ = 2.91 L

Explanation:

Given data:

Initial volume = 3.50 L

Initial temperature = 90.0°C (90+273 = 363 K)

Final temperature = 30.0 °C  ( 30 +273 = 303 K)

Final volume = ?

Solution:

V₁ = Initial volume

T₁  =  Initial temperature

V₂ = Final volume

T₂ = Final temperature

V₁/T₁  =  V₂/T₂

3.50 L / 363 K) =  V₂ / 303 K)

V₂ = 0.0096 L/K × 303 K

V₂ = 2.91 L

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The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem. For oxygen, the charge is 2-, the total considering its number of atoms is -24. Mn has a charge of +3. TO compute for Mn, we must achieve zero charge overall hence 3+3x-24=0 where x is the Cl charge. Cl charge, x is +7. 
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Toothpaste contains Sodium fluoride which is used to prevent tooth decay. How many grams are in 1 mole NaF?
nikitadnepr [17]

The answer is 42 grams of NaF are there in 1 mole.

<h3>What is a mole ?</h3>

A mole is defined as 6.022 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance.

Molar Mass , i.e. mass of 1 mole of NaF is sum of molar mass of Na and F

23 + 19

42 grams

Therefore 42 grams of NaF Sodium-fluoride are there in 1 mole.

To know more about mole

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6 0
2 years ago
Malia was able to make a paperclip float on the surface of water. What will most likely happen to the paperclip if a drop of dis
Arturiano [62]

Answer:

Its A

Explanation:

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5 0
3 years ago
0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +
Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

                     2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O

                       0.45 mol      0.55 mol                                ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

       Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

       Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81

From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

                        3 moles of H₂SO₄ ----------------  6 moles of water

                        0.55 moles of H₂SO₄ -----------    x

                        x = (0.55 x 6) / 3

                        x = 3.3 / 3

                       x = 1.1 moles of water

5 0
3 years ago
Determine the elements present in sodium hydrogen carbonate ​
Ilia_Sergeevich [38]

Sodium, hydrogen, carbon, and oxygen

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3 years ago
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