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pickupchik [31]
3 years ago
14

Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus

chloride. 2P +3Cl2 → 2PCl3 How much chlorine reacted with the phosphorus? 15.5 g 17.7 g 35.4 g 66.4 g
Chemistry
2 answers:
alex41 [277]3 years ago
5 0

Answer: 35.4 g

Explanation:

The balanced reaction is :

2P+3Cl_2\rightarrow 2PCl_3

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of phosphorous}=\frac{15.5g}{31g/mol}=0.50moles

\text{Moles of phosphorous chloride}=\frac{50.9g}{137g/mol}=0.372moles

2P+3Cl_2\rightarrow 2PCl_3

According to stoichiometry :

2 moles of phosphorous chloride are produced by = 3 moles of Cl_2

Thus 0.37 moles of phosphorous chloride are produced by=\frac{3}{2}\times 0.372=0.558moles of Cl_2

Mass of Cl_2=moles\times {\text {Molar mass}}=0.558moles\times 71g/mol=35.4g

Thus 35.4 g of chlorine reacted with the phosphorus

Leviafan [203]3 years ago
5 0

Answer:

c

Explanation:

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