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attashe74 [19]
2 years ago
10

Technical skills: knowledge base of sport rearrange our coaching skills from best (at the top) to worst (at the bottom) by dragg

ing each skill to where you think it belongs. this should help you identify your current strengths and limitations as a teacher/coach. after organizing each group of skills, describe steps you think you can take to enhance your strengths and being to address your limitations as a coach.
Physics
1 answer:
irakobra [83]2 years ago
5 0

The steps which enhance strengths and address limitations as a coach include:

  • Identifying weakness.
  • Setting goals.
  • Consistency.

<h3>Who is a Coach?</h3>

This is referred to a professional who gives special training about a particular subject or topic.

It is best to identify weakness and work towards improvement through determination and consistency.

Read more about Coach here brainly.com/question/26164090

#SPJ1

You might be interested in
Near the earth's surface, the electric field in the open air has magnitude 150 N/c and is directed down towards the ground. If t
kati45 [8]

Hi there!

Using the equation for the electric field produced by an infinite sheet of charge:

E = \frac{\sigma}{2\epsilon_0}

E = Electric field strength (150 N/C)

σ = Surface charge density (? C/m²)

ε₀ = Permittivity of free space (8.8542× 10⁻¹² C²/Nm²)

We can rearrange the equation to solve for the surface charge density (charge per unit area)

E = \frac{\sigma}{2\epsilon_0}\\\\\sigma = 2E\epsilon_0\\\\\sigma = 2(150)(8.8542*10^{-12}) = \boxed{2.656 \times 10^{-9} \frac{C}{m^2}}

3 0
2 years ago
In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot
Fittoniya [83]

Answer:

Q=7.9\times 10^{-10}\ C

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

A=5\times 10^{-3}\ m^2

We Capacitance given as

For air

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}

C_1=2.2\times 10^{-11}\ F

C_2=\dfrac{K\varepsilon _oA}{d}

C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F

C_2=6.6\times 10^{-11}\ F

Net capacitance

C=C₁+C₂

C=8.8\times 10^{-11}\ F

We know that charge Q given as

Q= C V

Q=12\times 6.6\times 10^{-11}\ C

Q=7.9\times 10^{-10}\ C

6 0
3 years ago
What is the mirror formula for curved mirrors
Reika [66]
The mirror formula for curved mirrors is:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where
f is the focal length of the mirror
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

The sign convention that should be used in order to find the correct values is the following:
- f: positive if the mirror is concave, negative if the mirror is convex
- d_i: positive if the image is real (located on the same side of the object), negative if it is virtual (located on the opposite side of the mirror)

3 0
3 years ago
Read 2 more answers
A clothing store has sensors that track how many people enter the store and cash registers that track how many purchases people
Ksivusya [100]

This information is valuable because Managers can use this customer data each month to figure out whether a larger or smaller percentage of visitors are buying clothes there.

<h3>What is the percentage of a number?</h3>

It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.

A clothes business contains sensors that count the number of customers entering the store and cash registers that count the number of transactions made daily.

Thus, data is useful because Managers may use it to determine if a greater or lesser proportion of customers are purchasing clothing each month. Therefore the correct answer is option A.

Learn more about the percentage here,

brainly.com/question/24159063

#SPJ1

8 0
1 year ago
The student throws one cannonball directly upward at 5.0 m/s and simultaneously throws the other cannonball directly downward at
Mademuasel [1]
Let the cannonball be thrown at a height of h above ground.
Then  the potential energy of the ball is
V = m*g*h
where
m = the mass of the ball
g = 9.8 m/s²

Also, the kinetic energy of the ball is
K = (1/2)mu²
where
u = 5 m/s, the vertical launch velocity.
Ignore wind resistance.

Because the total energy is preserved, the total energy (n the form of only kinetic energy) when the ball strikes the ground is
(1/2)mV²
where V = vertical velocity when the ball strikes the ground.

Expressions for both the initial and final energy are equal regardless of whether the ball s thrown downward or upward.
Therefore there is no difference in the landing speed. 

Answer: There is no difference.
8 0
3 years ago
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