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Gnom [1K]
3 years ago
5

Select all the correct answers.

Physics
1 answer:
WARRIOR [948]3 years ago
3 0
Oop i have no clue but i need to answer questions so that i can ask some :)
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At a constant pressure and a temperature of 280 K, the gas in a cylinder has a volume of 10.0 liters. If the volume of the gas i
IgorC [24]
560K I believe is the answer
6 0
3 years ago
A 100 kilowatt bulb burns for 3 hours how much energy did it use
belka [17]

Answer:

1.08×10⁹ J

Explanation:

From the question given above, the following data were obtained:

Power (P) = 100 kilowatt

Time (t) = 3 hours

Energy (E) =?

Next, we shall convert 100 kilowatt to Watts. This can be obtained as follow:

1 KW = 1000 W

Therefore,

100 KW = 100 KW × 1000 W / 1 KW

100 KW = 100000 W

Thus, 100 KW is equivalent to 100000 W.

Next, we shall convert 3 hrs to second (s). This can be obtained as follow:

1 h = 3600 s

Therefore,

3 h = 3 h × 3600 s / 1 h

3 h = 10800 s

Thus, 3 h is equivalent to 10800 s.

Finally, we shall determine the amount of energy consumed as follow:

Power (P) = 100000 W

Time (t) = 10800 s

Energy (E) =?

P = E/t

100000 = E / 10800

Cross multiply

E = 100000 × 10800

E = 1.08×10⁹ J

Therefore, 1.08×10⁹ J of energy was consumed.

4 0
3 years ago
Newton's second
Andru [333]

Explanation:

The second law states that the greater the mass of an object, the more force it will take to accelerate the object. There is even an equation that says Force = mass x acceleration or F=ma. This also means that the harder you kick a ball the farther it will go.

4 0
3 years ago
A thin film of cooking oil ( n = 1.47 ) is spread on a puddle of water ( n = 1.35 ) . What is the minimum thickness D min of the
zlopas [31]

Answer:

The minimum thickness of the oil is 77.55 nm

Explanation:

Given:

Refractive index of oil n_{o} = 1.47

Refractive index of water n_{w} = 1.35

Wavelength of light \lambda= 456 \times 10^{-9} m

From the equation of thin film interference,

The minimum thickness is given by,

    2n_{o} t = (n+\frac{1}{2}) \lambda

Where n = 0,1,2,3.........,t = thickness

Here we have to find minimum thickness so we use n = 0

     2n_{o} t  =( 0+\frac{1}{2} )\lambda

   t = \frac{\lambda }{4 n_{o} }

   t = \frac{456 \times 10^{-9} }{4 \times 1.47}

   t = 77.55 \times 10^{-9} m

   t  = 77.55 nm

Therefore, the minimum thickness of the oil is 77.55 nm

7 0
4 years ago
PLEASE ANSWER FIRST GETS BRAINLIEST
Oksanka [162]

Groups and periods are two ways of categorizing elements in the periodic table. Periods are horizontal rows (across) the periodic table, while groups are vertical columns (down) the table. Atomic number increases as you move down a group or across a period.

7 0
3 years ago
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