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Gnom [1K]
2 years ago
5

Select all the correct answers.

Physics
1 answer:
WARRIOR [948]2 years ago
3 0
Oop i have no clue but i need to answer questions so that i can ask some :)
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You are working on charge-storage devices for a research center. Your goal is to store as much charge on a given device as possi
zheka24 [161]

Answer:

Part A the answer is the dielectric constant.

Part B  Mica- mylar- paper- quartz

Explanation:

The capacity of a capacitor is given by

           C = ε ε₀ A / d

Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.

Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor

the flexibility of the material must also be taken into account

Part A the answer is the dielectric constant.

Pate B order the materials from best to worst

Mica. The best ever

Mylar Flexible

Paper Low capacity, low working voltage, flexible

Quartz high dielectric, but brittle

8 0
3 years ago
Can someone help me please​
iogann1982 [59]
Examine the water molecules in the animation. After the wave has passed which of the following is true?
6 0
3 years ago
Read 2 more answers
A box has a momentum of
Kipish [7]

Answer:

67.9 kg*m/s

Explanation:

Pi = 38 kgm/s

F = 88.3N and ∆t = 0.338s

Final momentum Pf = Pi + F∆t = 38 + (88.3)(0.338) = 38 + 29.8454

=) Pf = 67.8454 kgm/s = 67.85kg*m/s

Your answer is 67.9kg*m/s with three significant figures

hope this helps your troubles!

6 0
3 years ago
A 6.75 nC charge is located 1.99 m from a 4.46 nC point charge.
sladkih [1.3K]

Explanation:

Given that,

Charge 1, q_1=6.75\ nC=6.75 \times 10^{-9}\ C

Charge 2, q_2=4.46\ nC=4.46\times 10^{-9}\ C

The distance between charges, r = 1.99 m

To find,

The electrostatic force and its nature

Solution,

(a) The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

F=\dfrac{9\times 10^9\times 6.75\times 10^{-9}\times 4.46\times 10^{-9}}{(1.99)^2}

F=6.84\times 10^{-8}\ N

(b) As the magnitude of both charges is positive, then the force between charges will be repulsive.

Therefore, this is the required solution.

5 0
3 years ago
Please help with #8... Thanks in advance
schepotkina [342]
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:

the general equation of acceleration is:

vf = vi + at

assuming the initial velocity (vi) is zero, the equation becomes:

vf = at 

v = at
6 0
3 years ago
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