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matrenka [14]
3 years ago
12

Formula for cobalt (II) sulfide

Chemistry
1 answer:
Nostrana [21]3 years ago
7 0

i think the answer is COS2 tell me if im right or wrong

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The statements in the table summarize what Johannes Kepler stated in the early 1600s about the motion of planets.
SIZIF [17.4K]

Answer:

it's law

Explanation:

i got it wrong because i put the wrong answer but it was law or c

i hope this help's

4 0
3 years ago
Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water
barxatty [35]

Molarity after dilution : 0.0058 M

<h3>Further explanation </h3>

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M

5 0
3 years ago
Why do you think different liquids have different freezing points
Ganezh [65]
I think that different liquids have different freezing points because every liquid consists of different atoms and different things that make up the atom causing them to have different freezing points.
5 0
3 years ago
How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and
tangare [24]
The reaction between Na2S and CuSO4 will give us the balanced chemical reaction of,
                                     Na2S + CUSO4 --> Na2SO4 + CuS
This means that for every 78g of Na2S, there needs to be 159.6 g of CuSO4. The ratio is equal to 0.4887 of Na2S: 1 of CuSO4. Thus, for every 12.1g of CuSO4, we need only 5.91 g of Na2S. Thus, there is an excess of 9.58 g of Na2S. The answer is letter C. 
8 0
3 years ago
Read 2 more answers
True or false ? <br>an insoluble base will react with an acid. <br>​
Leno4ka [110]

Answer:

true maybe

Explanation:

#CarryOnLearning

7 0
2 years ago
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