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matrenka [14]
3 years ago
12

Formula for cobalt (II) sulfide

Chemistry
1 answer:
Nostrana [21]3 years ago
7 0

i think the answer is COS2 tell me if im right or wrong

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An action potential is regarded as an example of a positive feedback. Which of the following examples below best illustrates the
saul85 [17]

Answer:

A threshold stimulus will cause the opening of voltage gated sodium ion channels that will cause further depolarizing stimulus.This stimulus will open still more voltage gated sodium ion channels.

Explanation:

Action potential: It occurs when the potential of a membrane, of a specific cell location rapidly falls and raises. This depolarization stimuli later cause adjacent location to similarly depolarize. It is produce by the special types of voltage gated ion channels present in the cell's plasma membrane.

These channels are closed when the membrane potential near resting potential of the cell which is also called negative potential, but they fastly starts to open if the membrane potential increase to a defined threshold voltage, and depolarizing the potential of transmembrane.

When the channels are open, they allow sodium ions inward flow, which cause the changes in electrochemical gradient and producing further raise in the membrane potential. This then cause more channels to open.

4 0
3 years ago
Magnesium unites completely and vigorously with oxygen to form magnesium oxide, which contains 60% magnesium by weight. If 1.00
Dmitry_Shevchenko [17]

Answer:

After the reaction, there will 0.60 g of magnesium oxide and 0.25 g of oxygen gas present in the tube

Explanation:

Equation of the reaction between magnesium and oxygen is given as follows:

2Mg(s) + O₂(g) ---> 2MgO(s)

From the equation of reaction, 2 moles of magnesium reacts with i mole of oxygen gas to produce 1 mole of magnesium oxide

molar mass of magnesium is 24.0 g; molar mass of oxygen gas = 32.0 g; molar mass of magnesium oxide = 40.0 g

Therefore 24 g of magnesium reacts with 32 g of oxygen gas

I.00 g of magnesium will react with (24.0 / 32.0) * 1.00 g of oxygen = 0.75 g of oxygen gas.

Therefore, magnesium is the limiting reagent. Once it is used up, the reaction will stop and the excess oxygen will be left in the tube together with the product, magnesium oxide.

mass of excess oxygen = 1.00 - 0.75 = 0.25 g

mass of magnesium oxide formed = (24.0 / 40.0 g) * 1 = 0.60 g

4 0
2 years ago
If 0.0203 g of a gas dissolves in
ololo11 [35]

Answer:

P2 = P1*n2 / n1

       =1.02 atm *0.008 moles / 0.00113 moles

      = 7.22 atm

∴the new pressure will be 7.22 atm

Explanation:

7 0
2 years ago
Describe the two methods of active transport.
artcher [175]
Cars and bike yesyesyesyesyeyseyeyeyeyey
7 0
2 years ago
Read 2 more answers
A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
timofeeve [1]

Answer:

T = 36.393\,^{\textdegree}C

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

-Q_{iron} = Q_{gold}

-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)

-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C

-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C

2.438\cdot T = 88.727\,^{\textdegree}C

The final temperature is:

T = 36.393\,^{\textdegree}C

8 0
3 years ago
Read 2 more answers
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