1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nignag [31]
3 years ago
11

How many atoms of zirconium are in 0.3521 mol of zirconium?

Chemistry
1 answer:
lora16 [44]3 years ago
3 0

Answer:

2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

You might be interested in
A sample of neon gas occupies 105 L at 27°C under a pressure of
Viefleur [7K]

Answer: Volume occupied by given neon sample at standard condition is 123.84 L.

Explanation:

Given: V_{1} = 105 L,    T_{1} = 27^{o}C = (27 + 273) K = 300 K,     P_{1} = 985 torr

At standard conditions,

T_{2} = 273 K,     P_{2} = 760 K,        V_{2} = ?

Formula used to calculate the volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{985 torr \times 105 L}{300 K} = \frac{760 torr \times V_{2}}{273 K}\\V_{2} = \frac{94116.75}{760} L\\= 123.84 L

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.

8 0
3 years ago
Calculate the density of the aluminum cylinder with a diameter 0f 1.3 cm weighing 18 grams. Height of the cylinder is 5.2 Cm. Fi
Masja [62]

Answer:

Percent error = 3.7%

Explanation:

Given data:

Density of Al cylinder = ?

Weight of cylinder = 18 g

Diameter = 1.3 cm

Height = 5.2 cm

Actual density of Al = 2.7 g/cm³

Percent error = ?

Solution:

First of all we will calculate the volume of cylinder through given formula.

V = πr²h

r = diameter /2

V = 22/7 × (0.65 cm)²× 5.2 cm

V = 22/7 × 0.4225cm²× 5.2 cm

V = 6.89 cm³

Now we will calculate the density.

d = m/v

d = 18 g/ 6.89 cm³

d = 2.6 g/cm³

Percent error:

Percent error = measured value - actual value /actual value × 100

Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³  × 100

Percent error = 3.7%

Negative sign shows that measured or experimental value is less than actual value.

6 0
3 years ago
PLZ HEL I WILL GIVE BRAINLIEST
NemiM [27]

Answer: A material that readily transmits energy is a conductor, while one  that resists energy transfer is called an insulator .

i hope this will help u

pls add me as brainliest

8 0
3 years ago
Read 2 more answers
Give the name of the products formed
attashe74 [19]

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

The common thread joining all these reactions is that they are all electrophillic reactions. They are so called because the attacking agents in each reagent is an electrophile. Electrophiles are species that have electron deficient centers and are known to attack molecules that are high in electron density at regions of high electron density.

The benzene molecule has rich electron density. Any substituents that donates electrons to the ring improves the likelihood that benzene will undergo electrophillic substitution reactions while electron withdrawing substituents decrease the likelihood that benzene will undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with the attacking agents listed in the question are displayed in the answer section.

7 0
3 years ago
What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?
AURORKA [14]

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

<h3>What is the freezing point?</h3>

The temperature at which a liquid solidifies.

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

Learn more about the freezing point here:

brainly.com/question/3543605

#SPJ1

7 0
2 years ago
Other questions:
  • What do all of these things have in common? ______________________________ Bird, dog, tree, person, flower, grass, bacteria, cat
    9·1 answer
  • What is a substance formed when two or more elements combine and lose their distinct properties
    11·1 answer
  • Theoretically, a student performing a lab experiment was expected to get 9 g of product. Instead, the student obtained only 7.8
    13·1 answer
  • A body that weighs 6 Newton on the earth will weighs – on the moon in newton<br>​
    13·1 answer
  • Which of these compounds would most likely be found in a deposit of natural gas?
    6·1 answer
  • The prefix 'kilo-' means a thousand. So a kilo-gram is a thousand grams. 1 kilogram=1,000 grams How many kilograms is 1,008 gram
    9·1 answer
  • Find the density of a piece of glass with a mass of 500g and a volume of 200cm3
    9·1 answer
  • ASAP!
    10·1 answer
  • Which of these compounds would you expect to be most soluble in water? ch3ch2cl ch3ch2ch2ch3 ch3ch2ch2f ch3ch2ch2oh?
    6·2 answers
  • Read image for instructions A heterogeneous mixture B moleculeC liquid D homogeneous mixture
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!