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kaheart [24]
3 years ago
14

2 gallons is equal to how many liters

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

7.57082

Explanation:

its just the answer

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List the following bonds in order of increasing polarity (ionic character). Give the electronegativity values for each atom to j
barxatty [35]

Answer:

A = B < D < C

C - S

Cl - Cl

F ← H

Si → O

Explanation:

The polarity of a bond increases with the increase in the difference in electronegativity. The dipole moment is represented with an arrow pointing the more electronegative atom.

A: carbon-sulfur

C - S

ΔEN = |EN(C) - EN(S)| = |2.5 - 2.5| = 0

B: chlorine - chlorine

Cl - Cl

ΔEN = |EN(Cl) - EN(Cl)| = |3.0 - 3.0| = 0

C: fluorine – hydrogen

F ← H

ΔEN = |EN(F) - EN(H)| = |4.0 - 2.1| = 1.9

D: silicon - oxygen

Si → O

ΔEN = |EN(Si) - EN(O)| = |1.8 - 3.5| = 1.7

The order of increasing polarity is A = B < D < C.

4 0
3 years ago
A 5.50 gram sample of C2H6 gas has a volume of 2.50 L. If the sample is at 41.20C, what will it’s pressure be?
vovangra [49]
Multiple them divided by 2.50
8 0
3 years ago
Which conclusion is supported by the information in the graph?
Molodets [167]

Answer:

A. The cost of producing a kilowatt of power with fuel cell will be less than $30 in 2015

4 0
2 years ago
Write a word equation for the chemical reaction.<br><br> I’ll brainlist.
Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

Hope it helps.. if yes, plz mark me as brainliest

5 0
3 years ago
Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
melamori03 [73]

1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0
3 years ago
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