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Answer:
Theoretical yield for CO₂ is 5.10g
Explanation:
Reaction: 2C₆H₆(l) + 15O₂(g) → 12CO₂(g) + 6H₂O(g)
We convert the mass of oxygen to moles:
4.64 g /32 g/mol = 0.145 moles of O₂
Let's find out the 100% yield reaction of CO₂ (theoretical yield)
Ratio is 15:12. So let's make this rule of three:
15 moles of O₂ can produce 12 moles of CO₂
Therefore 0.145 moles of oxygen will produce (0.145 . 12) /15 = 0.116 moles
We convert the moles to mass: 0.116 mol . 44 g / 1mol = 5.10 g
Answer:
- <u><em>Option a. 6200 K</em></u>
Explanation:
<u>1) Data:</u>
- V₁ = 0.66 liter
- P₁ = 42.9 mmHg
- T = 261.2 K
- T₂ = ?
- V₂ = 7.63 liter
- P₂ = 872.15 mmHg
<u>2) Formula:</u>
Combined law of gases:
<u>3) Solution:</u>
T₂ = P₂ V₂ T₁ / (P₁ V₁)
T₂ = 872.15 mmHg × 7.63 liter × 261.2 K / ( 424.9 mmHg × 0.66 liter)
T₂ = 6198 K
- Rounding to 2 significant figures, that is 6200 K, which is the first choice.
